Renesas RL78/G1P Hardware User Manual page 732

RL78/G1P
Instruction Mnemonic
Group
Increment/ INC r
decrement
!addr16
ES:!addr16
saddr
[HL+byte]
ES: [HL+byte]
DEC r
!addr16
ES:!addr16
saddr
[HL+byte]
ES: [HL+byte]
INCW rp
!addr16
ES:!addr16
saddrp
[HL+byte]
ES: [HL+byte]
DECW rp
!addr16
ES:!addr16
saddrp
[HL+byte]
ES: [HL+byte]
Shift SHR A, cnt
SHRW AX, cnt
SHL A, cnt
B, cnt
C, cnt
SHLW AX, cnt
BC, cnt
SAR A, cnt
SARW AX, cnt
Notes 1. Number of CPU clocks (f
when no data is accessed.
2. Number of CPU clocks (f
Remarks 1. Number of clock is when program exists in the internal ROM (flash memory) area. If fetching the instruction
from the internal RAM area, the number becomes double number plus 3 clocks at a maximum.
2. cnt indicates the bit shift count.
R01UH0895EJ0100 Rev.1.00
Nov 29, 2019
Table 26-5. Operation List (13/18)
Operands Bytes
Note 1 Note 2
1
3
4
2
3
4
1
3
4
2
3
4
1
3
4
2
3
4
1
3
4
2
3
4
2
2
2
2
2
2
2
2
2
) when the internal RAM area, SFR area, or extended SFR area is accessed, or
CLK
) when the program memory area is accessed.
CLK
Clocks
 r  r+1
1
 (addr16)  (addr16)+1
2
 (ES, addr16)  (ES, addr16)+1
3
 (saddr)  (saddr)+1
2
 (HL+byte)  (HL+byte)+1
2
 ((ES:HL)+byte)  ((ES:HL)+byte)+1
3
 r  r – 1
1
 (addr16)  (addr16) – 1
2
 (ES, addr16)  (ES, addr16) – 1
3
 (saddr)  (saddr) – 1
2
 (HL+byte)  (HL+byte) – 1
2
 ((ES:HL)+byte)  ((ES:HL)+byte) – 1
3
 rp  rp+1
1
 (addr16)  (addr16)+1
2
 (ES, addr16)  (ES, addr16)+1
3
 (saddrp)  (saddrp)+1
2
 (HL+byte)  (HL+byte)+1
2
 ((ES:HL)+byte)  ((ES:HL)+byte)+1
3
 rp  rp – 1
1
 (addr16)  (addr16) – 1
2
 (ES, addr16)  (ES, addr16) – 1
3
 (saddrp)  (saddrp) – 1
2
 (HL+byte)  (HL+byte) – 1
2
 ((ES:HL)+byte)  ((ES:HL)+byte) – 1
3
 (CY  A
1 , A
0 m-1
 (CY  AX
1 , AX
0
 (CY  A
1 , A
7 m
 (CY  B
1 , B
7 m
 (CY  C
1 , C
7 m
 (CY  AX
, AX
1
15
 (CY  BC
1 , BC
15
 (CY  A
1 , A
0 m-1
 (CY  AX
1 , AX
0
CHAPTER 26 INSTRUCTION SET
Operation
 A  0) ×cnt
A
m , 7
 AX  0) ×cnt
, AX
m-1 m 15
 A  0) ×cnt
, A
m-1 0
 B  0) ×cnt
, B
m-1 0
 C  0) ×cnt
, C
m-1 0
 AX  0) ×cnt
, AX
m m-1 0
 BC  0) ×cnt
, BC
m m-1 0
 A  A
, A ) ×cnt
m 7 7
 AX  AX
, AX ) ×cnt
m-1 m 15 15
Flag
Z AC CY
× ×
× ×
× ×
× ×
× ×
× ×
× ×
× ×
× ×
× ×
× ×
× ×
×
×
×
×
×
×
×
×
×
713