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S3C2500B
31
0
0
0
0
0
The form of the shift field which might be expected to correspond to LSR #0 is used to encode LSR #32, which
has a zero result with bit 31 of Rm as the carry output. Logical shift right zero is redundant as it is the same as
logical shift left zero, so the assembler will convert LSR #0 (and ASR #0 and ROR #0) into LSL #0, and allow
LSR #32 to be specified.
An arithmetic shift right (ASR) is similar to logical shift right, except that the high bits are filled with bit 31 of Rm
instead of zeros. This preserves the sign in 2's complement notation. For example, ASR #5 is shown in Figure 3-
8.
31
30
The form of the shift field which might be expected to give ASR #0 is used to encode ASR #32. Bit 31 of Rm is
again used as the carry output, and each bit of operand 2 is also equal to bit 31 of Rm. The result is therefore all
ones or all zeros, according to the value of bit 31 of Rm.
Contents of Rm
Value of Operand 2
Figure 3-7. Logical Shift Right
Contents of Rm
Value of Operand 2
Figure 3-8. Arithmetic Shift Right
INSTRUCTION SET
5
4
0
carry out
5
4
0
carry out
3-13
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