AUTOMATIC TRANSMISSION
When, L = 90.50 mm (3.5630 in), 2 = 90.35 mm
(3.5571 in)
Calculation for 0.05 mm of clearance (0.0020 in)
H = (90.50 + 0.45) − 90.35 − 0.05 = 0.55
[H = (3.5630 + 0.0177) − 3.5571 − 0.0020 =
0.0217]
Calculation when clearance is 0.25 mm
(0.0098 in)
H = (90.50 + 0.45) − 90.35 − 0.25 = 0.35
[H = (3.5630 + 0.0177) − 3.5571 − 0.0098 =
0.0138]
After calculation, the value of "H" becomes be-
tween 0.35 mm (0.0138 in) and 0.55 mm (0.0216
in), therefore select two shims with thickness of 0.2
mm (0.010 in) or one shim with thickness of 0.5 mm
(0.020 in).
Adjusting shim
Part No.
33281AA001
33281AA011
TRANSFER CLUTCH
Thickness mm (in)
0.2 (0.008)
0.5 (0.020)
AT-96