Subaru 1600 Service Manual page 389

REAR WHEEL DRIVING SYSTEM (4WD MODEL)
NOTE:
Set the dial gauge needle to zero, using
a standard bearing or block of spec-
ified height in advance_
1 Weight (398227700)
2 Gauge (398237700)
3 Side bearing
A14-071
Fig. 8-34 Measuring side bearing
width
13) Press side bearing cone onto dif-
ferential carrier with Drift
(398487700) and Adapter
(398497701) included in Puller Set
(399527700).
1 Drnt(398487700)
2 Adapter (398497701)
A14-072
Fig. 8-35 Installing side bearing
14) Adjusting side bearing retainer
shims
a. The drive gear backlash and side
bearing preload can be determined
by the side bearing retainer shim
thickness.
b. When replacing differential carrier,
differential case, side bearing, and
side bearing retainer, obtain the
right and left retainer shim thick-
ness from the following formulas.
T1
A14·073
Fig. 8-36 Adjustment of side bearing
retainer shim
TI (Left) = (A+C+Gl-D)
x 0.01 + 0.76 - E (mm)
T
2
(Righ t) = (B + D + G2 )
x
om
+ 0.76 - F (mm)
T I & T
2 :
Thickness of left and
A&B
(' & D
E&F
right side bearing retainer
shim (mm)
Number marked on dif-
ferential case.
Number marked on dif-
ferential carrier.
Difference of width of
left
and
right side bearing
from standard width
20.0 mm, expressed in a
unit of 0.01 mm.
For example, if the
bearing measured width
is 19.89 mm, value of E
or F is as follows. 20.00
- 19.89 = 0.11 (E or F)
Gl
& G2:
Number marked on side
Side bearing
retainer
bearing retainer.
G
A 14-074
Fig.8-37 Location of markings
8-12
I f a number is not marked, regard it
as zero.
NOTE:
Use several shims to obtain the calcu-
lated thickness.
Side bearing retainer shims
Part No.
Thickness mm (in)
383475201
0.20 (0.0079)
383475202
0.25 (0.0098)
I
383475203
0.30 (0.0118)
383475204 OAO (0.0157)
383475205
0.50 (0.0197)
Example of calculation
Ex. 1
A=5, B=5, C=3, D=3,
Gl =4,G2 = I,E=O.IOmm
F = 0.15 mm
Left side
TI = (A+C+GI-D) x 0.01+0.76-E
= (5+3+4-3) x 0.01 +0.76-0.1 0
= 0.09+0.76-0.10
= 0.75 mm
The correct shims are as follows
Thickness
Q'ty
0.25 x 1
= 0.25
0.50 x 1
= 0.50
Total shim thickness = 0.75 mm
Right side
T2 = (B+D+G2) xO.01+0.76-F
= (5+3+1) xO.01+0.76-0.15
= 0.09+0.76-0.15
= 0.70 mm
The correct
Thickness
0.20
0.50
shims are as follows
Q'ty
x
1
x
1
Total shim thickness
Ex.2
0.20
= 0.50
= 0.70mm
A = 2, B = 3, C = 0, D = 3, GI = 2,
G2 =3, E=0.22mm,
F = 0.10 mm
Left side
TI = (A+C+GI -D)xO.OI +0.76-E
= (2+0+2-3)xO.OI+0.76-0.22
= 0.01+0.76-0.22
=0.55 mm
The correct shims are as follows
Thickness Q'ty
0.25 x 1 = 0.25
0.30 x 1 = 0.30
Total shim thickness = 0.55 mm