ABB 615 series Technical Manual page 248

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Section 4
Protection functions
242
Cross-polarizing as polarizing quantity
Table 240:
Equations for calculating angle difference for cross-polarizing method
Faulted
Used
Used
phases
fault
polarizing
current
voltage
A
I
V
A
BC
B
I
V
B
CA
C
I
V
C
AB
A - B
I
- I
V
- V
A
B
BC
CA
B - C
I
- I
V
- V
B
C
CA
AB
C - A
I
- I
V
- V
C
A
AB
BC
The angle difference between the polarizing quantity V
marked as φ in an example of the phasors in a single-phase ground fault where the faulted
phase is phase A. The polarizing quantity is rotated with 90 degrees. The characteristic
angle is assumed to be ~ 0 degrees.
Angle difference
ANGLE A
_
(
V
) -
ϕ
=
BC
GUID-330CBC28-7CE9-431A-9EC2-8590092DDAFF-ANSI V1 EN
ANGLE B
_
(
V
) -
ϕ
=
CA
GUID-3D93A608-FA6D-4F3E-9264-19776122A8E1-ANSI V1 EN
ANGLE C
_
(
V
) -
ϕ
=
AB
GUID-03176C00-8F5C-4791-A92C-9DBC0BA47EBF-ANSI V1 EN
_
(
-
ANGLE A
V
ϕ
=
BC
GUID-FA1C82F1-94F6-4669-8303-D465948F0611-ANSI V1 EN
ANGLE B
_
(
V
-
ϕ
=
CA
GUID-6D5785FC-2D25-48F9-B5D6-BD4E12A440E8-ANSI V1 EN
_
(
-
ANGLE C
V
ϕ
=
AB
GUID-B1524B24-5D74-4E0F-9432-7D19AC5A18C3-ANSI V1 EN
1MAC059074-MB A
o
(
I
) -
90
ϕ
ϕ
+
RCA
A
o
(
I
) -
90
ϕ
ϕ
+
B
RCA
o
(
I
) -
90
ϕ
ϕ
+
RCA
C
) -
(
-
) -
V
I
I
ϕ
ϕ
RCA
CA
A
B
V
) -
(
I
-
I
) -
ϕ
ϕ
AB
B
C
RCA
) -
(
-
) -
V
I
I
ϕ
ϕ
RCA
BC
C
A
and operating quantity I
BC
615 series ANSI
Technical Manual
o
90
+
o
90
+
o
90
+
is
A

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