Minimum Distance - HEIDENHAIN TNC 426 PB/M Technical Manual

Minimum distance

s
min
Jerk r
v
max
Example
6 – 112
To attain the maximum velocity, a minimum distance s
If the traversed distance is greater than s
speed is inserted at the time 2T
v
⋅ ⋅
max
------------
s = 2 v
min max
r
max
T 2T
r
Rapid traverse v = 30 000 mm/min (= 0.5 m/s); MP1010.x = 30000
max
Max. jerk with velocity v > 20 000 mm/min (= 0.33 m/s) r
MP1090.1 = 70, MP1092 = 20000
Max. jerk r = 35 m/s
max2
Maximum attainable acceleration a
⋅
a = v r
max1 max max1
Maximum attainable acceleration a
20 000 mm/min):
⋅
a = v r
max2 max max2
Distance s required to attain rapid-traverse velocity:
min
v
⋅ ⋅ max
----------- -
s = 2 v
min max
r
max
Note
The rectangular jerk curve is rounded through the use of a nominal position
value filter (MP1096 ≠ 0). As a result, acceleration is reduced and the
minimum distance required for attaining the maximum velocity is
increased.
, a movement with constant
min
. The minimum distance is:
r
r
3
during machining; MP1090.0 = 35
during rapid traverse:
max1
m m
⋅
= 0.5 ----- - 70 ------ = 5.92
s 3
s
during machining (v up to
max2
m m
⋅
= 0.33 ----- - 35 ------ = 3.40
s 3
s
m
0.5 ----- -
m s
⋅ ⋅
---------------
= 2 0.5 ----- -
s m
70 ------ -
3
s
HEIDENHAIN Technical Manual TNC 426, TNC 430
must be traversed.
min
Distance s
Velocity v
3T 4T
r r
Acceleration a
= 70 m/s
max1
m
------
2
s
m
------
2
s
= 0.085 m = 85 mm
t
3
;