Subaru SVX 1992 Manual page 634

3-4 [W2F1] AWD SYSTEM
13) Press side bearing cone onto differential case with
DRIFT and ADAPTER included in PULLER SET
(399527700) .
DRIFT (398487700)_`
00
® V
ADAPTER (398497701)
C3-181
Fig . 74
14) Adjusting side bearing retainer shims
(1) The drive gear backlash and side bearing preload
can be determined by the side bearing retainer shim
thickness.
(2) When replacing differential case, differential car-
rier, side bearing and side bearing retainer, obtain the
right and left retainer shim thickness from the follow-
ing formulas .
T,
` A
. ~' D C
J . '
-i"-- ,
18
''. F
T2
B3-185
Fig. 75
T, (Left) = (A + C + G, - D) x 0.01 + 0.76 - E
(mm)
TZ (Right) = (B + D + GO x 0 .01 + 0 .76 - F (mm)
T, £t Tz :
Thickness of left and right side bearing
retainer shim (mm)
A £r B .
Number marked on differential carrier .
C Er D . Number marked on differential case .
E £r F . Difference of width of left and right side
bearing from standard width 20 .0 mm,
expressed in a unit of 0.01 mm . For
example, if the bearing measured width
is 19 .89 mm, value of E or F is as follows .
20 .00 - 19 .89 = 0.11 (E or F)
G,£r GZ . Number marked on side bearing re-
tainer .
Differential carrier
__ Differential case
eaeo
0
e
U
Side bearing
°
0 , o
retainer ,
C3-179
Fig. 76
If a number is not marked, regard it as zero .
Use several shims to obtain the calculated thickness .
Side bearing retainer shims
Part No.
Thickness mm (in)
383475201 0.20 (0.0079)
383475202
0.25 (0 .0098)
383475203
0.30 (0 .0118)
383475204 0.40 (0 .0157)
383475205
0.50 (0 .0197)
Example of calculation
Ex . 1
A= 5,B= 5,C= 3,D= 3, G, = 4,G2= 1,
E= 0.10 mm, F= 0.15 mm
Left side
T,= (A+ C+ G,- D) x0 .01 + 0 .76-E
= (5+ 3+ 4-3)x0 .01 + 0 .76-0 .10
= 0.09 + 0.76 - 0 .10 = 0 .75 mm
The correct shims are as follows
Thickness
Qty
0.25 x 1 = 0.25
0.50 x 1 = 0.50
Total shim thickness = 0 .75 mm
Right side
Tz= (B+ D+ GO x0 .01 + 0 .76-F
= (5+ 3+ 1)x0 .01 + 0.76-0.15
= 0 .09 + 0.76 - 0.15
= 0.70 mm
The correct shims are as follows
Thickness Qty
0.20 x 1
= 0.20
0.50 x 1 = 0.50
Total shim thickness = 0 .70 mm
Ex . 2
A = 2, B = 3, C = 0, D = 3, G, = 2, GZ = 3,
E= 0.22 mm, F= 0.10 mm
Left side
T,= (A+ C+ G,- D) x0 .01 + 0 .76-E
= (2+ 0+ 2-3)x0 .01 + 0.76-0 .22
=0 .01+0.76-0 .22
= 0.55 mm
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