Delta ASDA-B2 Series User Manual page 35

Chapter 2 Installation
Servo Drive
(kW)
ECMA-E△1830
ECMA-F△1830
3.0
ECMA-E△1835
1.0 ECMA-F△1308
2.0 ECMA-F△1313
2.0 ECMA-F△1318
3.0 ECMA-F△1830
0.4 ECMA-G△1303
0.75 ECMA-G△1306
1.0 ECMA-G△1309
2
Eo = J x wr /182 (joule), Wr : r/min
Assume that the load inertia is N times to the motor inertia and the motor decelerates
from 3000r/min to 0, its regenerative energy is (N+1) x Eo. The consumed regenerative
resistor is (N+1) × Eo - Ec
the power of regenerative resistor it needs is 2× ((N+1) x Eo - Ec) / T.
Followings are the calculation procedure:
Step
Set the capacity of regenerative
1
resistor to the maximum
Set T cycle of back and forth
2
3 Set the rotational speed wr
4 Set the load/motor inertia ratio N
Calculate the maximum
5
regenerative energy Eo
Set the absorbable regenerative
6
Calculate the needful capacitance
7
of regenerative resistor
Take 400W as the example, the cycle of back and forth operation is T = 0.4sec, the
maximum speed is 3000r/min and the load inertia is 7 times to the motor inertia. Then,
the needful power of regenerative resistor is 2 × ((7+1) × 1.68 – 8) / 0.4 = 27.2 W. If it is
smaller than the built-in capacity of regenerative resistor, the built-in 60W regenerative
2-14
Rotor Inertia
Servo Motor
J (× 10
joule. If the cycle of back and forth operation is T sec, then
Procedure
operation
energy Ec
Regenerative
power from empty
load 3000r/min to
2
-4
kg.m )
stop
Eo (joule)
54.95 217.73
54.95 217.73
54.95 217.73
13.6 67.25
20.0 98.90
24.9 123.13
54.95 217.73
8.17 40.40
8.41 41.59
11.18 55.29
Calculation and Setting Method
Set P1-53 to the maximum value
Enter by the user
Enter by the user or read via P0-02
Enter by the user or read via P0-02
Refer to the above table
2 x ((N+1) x Eo – Ec) / T
Max.
regenerative
power of
capacitance
Ec(joule)
28
28
28
18
21
21
28
14
18
2
Eo= J * wr /182
Revision May, 2018
ASDA-B2
8