Matching Mistake 1 - HP FlexNetwork MSR Series Configuration Manual

[Sysname-voice-ivr] node 9 call
[Sysname-voice-ivr-node9] extension 1 call 300
[Sysname-voice-ivr-node9] quit
Analysis
When the IVR process jumps to node 8, it has already jumped for more than eight nodes, the
eight-level limit is reached, and the call is terminated.
Solution
Avoid the configuration of making the IVR process jump from node to node for more than eight times.

Matching mistake 1

Symptom
Configure the node to execute both normal secondary call by matching the number and extension
secondary call. When the subscriber dials 1201, the node does not execute the secondary call to the
number 7745231.
Following are the configurations:
[Sysname-voice-ivr] node 1 call
[Sysname-voice-ivr-node1] call-normal matching
[Sysname-voice-ivr-node1] extension 1201 call 7745231
Analysis
When the subscriber dials 1201, the node executes an extension secondary call as soon as it
receives the number 120.
Solution
There are some short numbers for special usage, such as 120, 110, and 114. Do not configure them
as the prefixes of extension numbers. Otherwise, when subscribers dial extension numbers with
these prefixes, the node executes the normal secondary call immediately.
Matching mistake 2
Symptom
Configure the node to execute both normal secondary call by matching the terminator # and
extension secondary call. When the subscriber dials the number 774566, the node always connects
the subscriber to the number 7745231.
Following are the configurations:
[Sysname-voice-ivr] node 1 call
[Sysname-voice-ivr-node1] call-normal terminator #
[Sysname-voice-ivr-node1] extension 7 call 7745231
Analysis
The extension secondary call takes precedence over the normal secondary call. When the
subscriber dials the number 7, the node matches it with the extension number 7, and connects the
subscriber to the number 7745231 instead of 7745666.
Solution
When the length of the extension number is shorter than that of the normal number, the extension
number cannot be configured as the prefix of the normal number. To solve the above problem, you
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