ABB REG316 4 Series Operating Instructions Manual page 88

Numerical generator protection
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Example:
The compensation for the currents of a three-winding trans-
former Yd5y0 is as follows:
s1 = Y
s2 = d5
s3 = y0
compensation matrix
for winding 1
compensation matrix
for winding 2
compensation matrix
for winding 3
The function currents then become:
Function currents (calculated)
æ
ö
I
r
1
ç
÷
I
ç
÷
Winding 1:
s
1
ç
÷
è
I
ø
t
1
æ
ö
I
r
2
ç
÷
I
ç
÷
Winding 2:
s
2
ç
÷
è
ø
I
t
2
æ
ö
I
r
3
ç
÷
I
ç
÷
Winding 3:
s
3
ç
÷
è
I
ø
t
3
3-50
REG 316*4 1MRB520049-Uen / Rev. F
CBC results from
Table
= C = (1 -1 0)
with an amplitude factor of
= B = (-1 0 0)
with an amplitude factor of 1
= C = (1 -1 0)
with an amplitude factor of
æ
ç
1
=
ç
3
ç
è
æ
ç
=
1
ç
ç
è
æ
ç
1
=
ç
3
ç
è
3.5.1.2, i.e. the
(see Table 3.5.1.1)
(see Table 3.5.1.1)
(see Table 3.5.1.1)
Currents measured at
the c.t's
ö
æ
ö
-
1
1 0
I
R
1
÷
ç
÷
-
0
1
1
I
ç
÷
÷
S
1
÷
ç
÷
-
ø
1 0
1
è
I
ø
T
1
æ
ö
ö
-
1 0
0
I
R
2
÷
ç
÷
-
0
1 0
I
ç
÷
÷
S
2
÷
ç
÷
-
ø
è
ø
0
0
1
I
T
2
æ
ö
-
ö
1
1 0
I
R
3
÷
ç
÷
-
0
1
1
I
ç
÷
÷
S
3
÷
ç
÷
-
1 0
1
ø
è
I
ø
T
3
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