Setting Options Of Cam Generator - Baumuller b maXX BM3000 Operating Manual

4.6
Set Value Generators

4.6.5.4 Setting options of cam generator

Cyclical processing
1 Time controlled processing modes
2 Parameter-controlled processing mode
428 Parameter manual b maXX BM3000
Document no.: 5.12001.07
of 820
If cyclical processing is selected in parameter Z159.2–, the cam generator jumps back
to the first table index after reaching the maximum table index Z159.4–. The cam gen-
erator then restarts processing. For more information, referring to the cyclical curve off-
set at a table index jump see chapter
If the input parameters are float parameters, then the selection of the cyclical process-
ing does not effectuate the behavior of float parameters as described in chapter
ZParameter-controlled processing–
Additionally to the base value
parameters of an integer data type, a mask is generated to specify the index. This acts
on the input parameters. This mask operates after subtraction of the base value and
after shift operation. Referring to mask operation only those bits are used to specify the
index, which are required to activate the curve index.
Example:
Value input parameter = 0x0075AB39 
Initial situation:
Base value
Shift factor
Count supporting points
The following index results after subtraction of base value and after shift operation:

Index = 0x0075AB39 0xA000
Having 512 supporting points applies to 512 = 2
spond to the 512 supporting points of the cam. This mask, which contains 9 bits is gen-
erated by the controller. If there were 256 supporting points, then in conclusion the
mask will have 8 bits.
Example:
Index = 0xEA16 & 0x1FF
Index 22 is the active table index.
If the cyclical processing is not selected, the active table index is the index 0xEA16 =
59926. This index is greater than the maximum index of (count supporting points - 1)
= 511. The active table index is limited to a maximum index of 511 at non-cyclical pro-
cessing.
ZCyclical curve offset–
on page 427.
Z159.14–
and to the shift factor
Z159.14–
= 0xA000 
Z159.15–
= 7 
Z159.5–
 >> 7
– =
9
. Therefore, 9 bits are required to re-
= 0x16 = 22
on page 429.
Z159.15–
at the input
= 512
0xEA16
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