ABB AC500 V3 Hardware Manual page 923

The total current can be calculated as follows:
I = I
Total
with the assumptions
I
LOGIC
I
I/O bus
and
I = I
UP
+ I
LOAD7
If one assumes that all outputs are switched on and are operated with their maximum permitted
load currents (under compliance with the maximum permitted currents at the supply terminals),
then the following values are the result for an example shown above:
CPU / communication module part
CPU
C1
C2
C3
C4
I/O module part
Analog1
Analog2
Analog3
Analog4
Digital1
Digital2
Digital3
S columns
*) All values in this column are exemplary values
2.4.5.2 Dimensioning of the fuses
To be able to select the fuses for the station correctly, both the current consumption and the
inrush currents (melting integral for the series-connected fuse) must be taken into consideration.
2022/01/31
Overall information (valid for complete AC500 product family) > Power consumption of an entire station
Because of the high total current consumption of the digital I/O modules (from
UP = 24 V DC), the supply is divided up into several electric circuits fused
separately.
The maximum permitted total current over the supply terminals of the I/O ter-
minal units is 8 A.
+ I
LOGIC UP
= I + I + I + I
CPU I/O bus C1 C2
= Number of expansion modules × Current consumption through the I/O bus per module
+ I + I + I
UP1 LOAD1 UP2 LOAD2
I *)
CPU
0.110 A
-
-
-
-
-
-
-
-
-
-
-
0.110 A
S I
≈ 0.4 A
LOGIC
I ≈ 25.4 A
Total
3ADR010278, 3, en_US
+ I + I (CPU + communication modules + I/O bus)
C3 C4
+ I + I + I + I
UP3 LOAD3 UP4
I *) I
Cx I/O bus
- -
0.050 A -
0.085 A -
0.050 A -
0.050 A -
- 0.002 A
- 0.002 A
- 0.002 A
- 0.002 A
- 0.002 A
- 0.002 A
- 0.002 A
0.235 A 0.014 A
System assembly, construction and connection
+ I + I + I
LOAD4 UP5 LOAD5 UP6
*) I *)
UPx
-
-
-
-
-
0.150 A
0.150 A
0.100 A
0.100 A
0.050 A
0.050 A
0.050 A
0.650 A
S I
≈ 25 A
UP
+ I + I
LOAD6 UP7
I *)
LOADx
-
-
-
-
-
-
0.160 A
0.080 A
0.080 A
8.000 A
8.000 A
8.000 A
24.320 A
923