(4) When "mm" is set as the control unit for conveyor drive
(calculation including
When the belt conveyor drive is used, the conveyor diameter is 135mm,
the pulley ratio is 1/3, the motor is HG-KR (4194304PLS/rev) and the
reduction ratio of the reduction gear is 7/53.
M
Reduction ratio 7/53
As the travel value of the conveyor is used to exercise control, set "mm"
as the control unit.
First, find how many millimeters the load (machine) will travel (
the motor turns one revolution (AP).
AP (Number of pulses per rotation) = 4194304 [PLS]
S
Substitute this for the above expression (1).
At this time, make calculation with the reduction ratio 7/53
remaining as a fraction.
AP
S
Here, make calculation on the assumption that
3.141592654.
AP
S
AL has a significant number to first decimal place, round down numbers to
two decimal places.
AP
S
Thus, AP, AL and AM to be set are as follows.
AP = 166723584 ....[Pr.2]
AL = 742201.2 .......[Pr.3]
AM = 1 ..................[Pr.4]
Pulley ratio 1/3
(Movement amount per rotation)
AP
=
AL AM
AP
=
AL AM
AP
=
AL AM
13 - 17
Chapter 13 Control Sub Functions
)
Belt
conveyor
= 135000.0 [
m]
= 135000.0 [
m]
4194304 [PLS]
=
135000.0 [ m]
4194304 53 3
=
135000.0
7
166723584
=
236250
166723584
=
742201.2645075
166723584
=
=
742201.2
135mm
S
) when
Reduction ratio
7/53
1/3
1/3
7/53 1/3
is equal to
166723584 (AP)
742201.2 (AL) 1(AM)