Mitsubishi Electric MDS-E Series Instruction Manual page 359

MDS-E/EH Series Instruction Manual
6 Spindle Adjustment
CAUTION
1. Note that the inertia (J) is a quarter of "GD
2
Ex.) When "GD " is 0.2 [kg•m
2. If the AC input power voltage to the power supply is low, or if the input power impedance is high, the acceleration/
deceleration time may be long. (Especially, the acceleration/deceleration time of the deceleration output range may be
long.)
3. For the actual measurement in comparison with the theoretical value, perform under the same condition as the
calculated load inertia of Jall. The acceleration/deceleration time differs according to the inertia. When performing the
measurement with a workpiece or tool installed to the spindle, confirm that the acceleration/deceleration time has been
calculated when the total inertia is included in the installed workpiece and tool.
[Calculation example]
Calculate the acceleration/deceleration time from 0 to 10000[r/min]
for an spindle motor having the output characteristics shown on the
right when the motor inertia is 0.0148 [kg•m
shaft conversion load inertia is 0.05 [kg•m
Po = (Short-time rated output) × 1.2 = 5500 × 1.2 = 6600 [W]
J = (Motor inertia) + (load inertia)
all
= 0.0148 + 0.05 =0.0648 [kg•m
-2
1.097 x 10
t1 =
Po
-2
1.097 x 10
t2 =
-2
1.097 x 10
t3 =
3 x Po x N2
Thus,
t = t1 + t2 + t3 = 0.242 + 1.818 + 4.691 = 6.751 [s]
IB-1501229-F
2
".
2
], the inertia is "0.2 / 4 = 0.05 [kg•m
2
], and when the motor
2
].
2
]
2
x J x N1 1.097 x 10
all
=
2 2
x J x (N2 - N1 ) 1.097 x 10
all
=
2 Po
3 3
x J x (N3 - N2 ) 1.097 x 10
all
=
2
]".
8.0
6.0
5.5
4.0
3.7
2.0
0
-2 2
x 0.0648 x 1500
= 0.242 [s]
6600
-2 2
x 0.0648 x (6000 - 1500
2 6600
-2 3
x 0.0648 x (10000 - 6000
3 x 6600 x 6000
328
15-minute
4.1
rating
2.8
Continuous
rating
0 1500 6000 10000
Rotation speed [ r/min ]
Spindle motor characteristics
2
)
= 1.818 [s]
3
)
= 4.691 [s]