Danfoss MCO 305 Design Manual page 43

MCO 305 Design Guide
How to Edit a curve for the Slave Synchronization
1. Set the FC 300 with the required parameters and save these parameters with Parameters → Save to file
with the extension "zbc".
2. This .zbc file must be open in the CAM-Editor.
3. Determine the gearing factor of the master in MU units.
Gearing factor = 5/1
Encoder resolution (Incremental encoder) = 500
One revolution of the roller is 360 degrees. We are going to work with a resolution of 1/10 degrees.
This means that we are dividing one revolution of the roller into 3600 work units:
Scaling factor = 3600
Gearing Factor ∗ Encoder
Scaling Factor
Enter these whole number values in the index card → Synchronization:
Par. 33-10 Syncfactor Master
Par. 33-11 Syncfactor Slave
4. Enter the gearing factor of the slave in UU units:
The input should be possible in 1/10 mm resolution.
The drive is connected with the conveyor belt by means of a gearing of 25:11; i.e. the motor makes 25,
the drive pulley 11 revolutions.
Gearing factor = 25/11
Incremental encoder directly on the master drive; encoder resolution = 4096
The drive pulley has 20 teeth/revolution, 2 teeth correspond to 10 mm, thus 1 revolution corresponds
to = 100 mm conveyor belt feed or 1000/10 mm.
Thus, the scaling factor is 1000
Gearing Factor ∗ Encoder
Scaling Factor
Enter these values in the index card → Encoder Data:
Par. 32-12 User Unit Numerator
Par. 32-11 User Unit Denominator
5. Determine a whole number factor for the intervals in the index card → Curve Data so that the Fix points
are on the interpolation points.
A complete cycle length of the master is 360 degrees; this corresponds to 3600 MU.
For a master cycle length of 3600, the → Number of Intervals = 36 produces a reasonable interval time
of 27.7 ms. Set these two values using the "Set" button in the Curve Data index card.
6. Define → Fix points for the roller (slave) and
the conveyor belt (master). The function
→ Snap on Grid should be activated.
7. Master and slave must run synchronously with
the same velocity between the master posi-
tions 1200 to 2400. For this, you need to have
a straight line that is determined with two tan-
gent points. Double-click in the column → Type
for the fixpoint at position 2400.
__ Functions and Examples __
Resolution ∗ 4
qc = 1 MU
= 25
= 9
Resolution ∗ 4
qc = 1 UU
= 2048
= 55
®
MG.33.L5.02 – VLT is a registered Danfoss trademark
Point Master Slave
1 0 0
2 1200 1500
3 2400 2500
4 3600 4000
Point Master Slave
1 0 0
2 1200 1500
3 2400 2500
4 3600 4000
Type
C
C
C
C
Type
C
T
T
C
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