Juniper MX2010 Hardware Manual page 351

To check the DIP switch position:
1. Issue the show chassis power command and check to see how many feeds are connected. The following
example shows there are two AC input feeds connected for PEM 0 and one AC input feed connected
for PEM 1. This indicates that the DIP switch for PEM 0 is in position 1 and the DIP switch for PEM 1
is in position 0. These are the proper settings.
# run show chassis power
PEM 0:
State: Online
AC input: OK (2 feed expected, 2 feed connected)
Capacity: 4100 W (maximum 4100 W)
DC output: 855 W (zone 0, 15 A at 57 V, 20% of capacity)
PEM 1:
State: Online
AC input: OK (1 feed expected, 1 feed connected)
Capacity: 1700 W (maximum 4100 W)
DC output: 969 W (zone 1, 17 A at 57 V, 57% of capacity)
2. Issue the show chassis alarms command to see if there are any active alarms on the DIP switch:
> show chassis alarms
4 alarms currently active
Alarm time Class Description 2013-01-11 14:48:26 UTC Minor PEM 0 Dipswitch 0
Feed Connection 2
3. If the show chassis alarms output shows an alarm on Dipswitch, issue the show chassis power command
to check the DIP switch position.
# run show chassis power
PEM 0:
State: Online
AC input: OK (1 feed expected, 2 feed connected)
Capacity: 4100 W (maximum 4100 W)
DC output: 855 W (zone 0, 15 A at 57 V, 20% of capacity)
In this example, the DIP switch is in the wrong position since there is one AC feed expected but two
AC feeds are connected. Change the DIP switch to position 1. This should clear the alarm.
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