Mitsubishi Heavy Industries SRK25GZ-L1 Handbook page 647

2000 air conditioning & heat pump machinery handbook
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(2) Correction of cooling capacity in relation to air flow rate control (fan speed)
Coefficient: 1.00 at High, 0.95 at Low
(3) Correction of cooling capacity in relation to one way length of refrigerant piping
It is necessary to correct the cooling capacity in relation to the one way equivalent piping length between the indoor and outdoor
units.
Equivalent piping length
FDU308 type
FDU408 type
FDU508 type
Note (1) Equivalent piping length can be obtained by calculating as follows.
308 series [ø15.88 (5/8")]: Equivalent piping length = Real piping length + (0.10 × Number of bends in piping)
408, 508 series [ø19.05 (3/4")]: Equivalent piping length = Real piping length + (0.15 × Number of bends in piping)
[Equivalent piping length < Limitation length of piping + 5 m]
(4) When the outdoor unit is located at a lower height than the indoor unit in cooling operation, the following values
should be subtracted from the values in the above table.
Height difference between the indoor unit and
outdoor unit in the vertical height differenc
Adjustment coefficient
Piping length limitations
Item
Max. one way piping length
Max. vertical height difference
Note (1)Values in the table indicate the one way piping length between the indoor and outdoor units.
How to obtain the cooling capacity
Example: The net cooling capacity of the model FDU308CEN-A with the air flow "High", the piping length of 15 m, the outdoor
unit located 5 m lower than the indoor unit, indoor wet-bulb temperature at 19.0°C and outdoor dry-bulb temperature
35°C is
Net cooling capacity = 7100
(1)
m
5
10
1.0
0.99
1.0
0.995/0.99
1.0
0.99/0.985
Model
×
FDU308CEN-A
Air flow "High"
15
20
0.98/0.975
0.97/0.965
0.96/0.95
0.985/0.98
0.98/0.97
0.97/0.96
0.975/0.97
0.965/0.955
0.95/0.94
5 m
10 m
0.01
0.02
All models
30 m
15 m
×
1.00
(0.98 – 0.01)
Length 15 m.
Height difference 5 m
FDU-C
(50/60Hz)
25
30
35
0.95/0.94
0.94/0.925
0.965/0.95
0.955/0.94
0.94/0.925
0.925/0.91
15 m
0.03
×
1.0
= 6887 W
Factor by air temperatures
645

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