Mitsubishi Heavy Industries SRK25GZ-L1 Handbook page 790

FDC-HKX
19.2.6 Selection chart
(1) Correct the cooling and heating capacity in accordance with the conditions as follows.The net cooling and heating capacity can
be,obtained in the following way.
Indoor unit
Each indoor unit = System performance ×
Outdoor unit
System performance =
Note(1) Refer to page 788 and 802 for the correction coefficient.
(a) Coefficient of cooling and heating capacity in relation to temperatures
(b) Correction of cooling and heating capacity in relation to one way length of refrigerant piping.
Equivalent piping length [m]
Cooling
Heating
Equivalent piping length [m]
Cooling
Heating
Equivalent piping length [m]
Cooling
Heating
Note (1) Equivalent piping length can be obtained by calculating as follows.
quivalent piping length = Real gas piping length + Number of bends in gas piping × Equivalent piping length of bends.
Equivalent length of each joint
Gas piping size
Joint (90˚elbow)
788
Indoor unit capacity when operating simultaneously.
Performance from connected capacity × correction coefficient from indoor and out-
door temperature conditions × (correction coefficient from piping distance – correc-
tion coefficient from different between indoor and outdoor temperature) × (correc-
tion coefficient from condensation when heating
1.3
1.2
1.1
1.0
0.9
0.8
0.7
0.6
43
40
35
30
25
20
0
-5
14
Indoor air W.B. temperature °C W.B.
27
25
20
15
10
-15 -10 -5
Outdoor air W.B. temperature °C W.B.
(1)
5 10
1.0 0.99
1.0 1.0
55 60
0.875 0.865
0.985 0.98
105 110
0.745 0.74
0.96 0.955
φ12.7
0.10
Indoor unit capacity
Cooling
Heating
Applicablerange
16 18 20
JIS Standard Condition
0 5 10
JIS Standard Condition
15 20 25 30
0.975 0.965 0.95 0.94
1.0 1.0 1.0 0.995
65 70 75 80
0.85 0.84 0.825 0.815
0.98 0.975 0.975 0.97
115 120 125
0.725 0.715 0.7
0.955 0.95 0.95
φ15.88 φ19.05
0.10 0.15
26
24
22
15
35 40 45
0.925 0.915 0.9
0.995 0.99 0.99
85 90 95
0.8 0.79 0.775
0.97 0.965 0.965
Unit : m/one part
φ25.4 φ28.58
0.15 0.20
50
0.89
0.985
100
0.765
0.96