gefran AFE200 4 Series Instruction Manual page 190

> Total electrical power absorbed:
P
P
> Total power requested by the DC-link side:
P
400 Vac mains, corresponding DC-link value = 650Vcc
I
I
max
The AFE200 must be able to deliver a current of ≥ 83A with an overload current
value of ≥ 123A.
Choose the size with the appropriate characteristics from the section
trical data" on page
AFE200 - 4450.
> Choosing the drive:
Since the motors are used at below the rated power, the following inverters are
suitable:
Motor 1
Choose the size with the rated current required by the motor (≥ 31.4A) from the
catalogue ADV & AFE (section ADV200-DC "2.7 Output Data").
With a 650 Vdc drive:
ADV-3185-...-DC (In = 34.2A, OK).
Motor 2
Choose the size with the rated current required by the motor (≥ 33.3A) from the
catalogue ADV & AFE (section ADV200-DC "2.7 Output Data").
With a 650 Vdc drive:
ADV-3185-...-DC (In = 34.2A, OK).
Motor 3
Choose the size with the rated current required by the motor (≥ 34.4A) from the
190
η
= 0,96
m
i = 43a
m
Application: continuous load, Pcont= 80%
Requested overload = 130%
(P * P
outm
=
tot
η
m
(18.5 * 0.85)
=
tot
0.95
P
tot
=
dc
η
d
P * 1000
dc
=
tot
Vdc-link
(P * I
outm ovld
=
Vdc-link * η
m
170:
: i 1 = 37A * 85% = 31.4A
m
: i 2 = 37A * 90% = 33.3A
m
: Im3 = 43A * 80% = 34,4A
AFE200 • Instruction Manual
)
cont
(18.5 * 0.9)
+ +
0.95
52.4
+ = 54 kW
0.97
54000
+ = 83 A
650
) (18500 * 1.3)
=
650 * 0.95
(22 * 0.8)
= 52.4 kW
0.96
(18500 * 1.3) (22000 * 1.3)
+ +
650 * 0.95 650 * 0.96
= 123 A
"10.6 Elec-