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also be used to determine the ROS board
on which any given address is located.
Using out last example, address 2787,
you can see that it appears on ROS board
29.
Our first address of 0712 is found
on ROS board 7.
By doing some simple arithmetic,
Figure
3-39
may be used for addresses
greater than 4032.
Take, for example,
address 6789.
Subtract 4096 from this.
The result is 2693.
This is the equi-
valent address in the first 41< module.
The three inputs to the decoder circuit
for this address are C2, B2, and A4.
The address is located on ROS board 28
of the second module, 41<-81<.
REVIEW QUESTIONS - ROS ADDRESSING
1.
How many words are read out by the
address in ROAR?
2.
What is the maximum am.ount of ROS
storage?
3.
4.
5.
3-60
A driver is selected by means of a
line and a
line.
ROAR consists of ______ __ latches.
How many drivers are used for each
ROS board?
6.
How many sense amplifiers and sense
amplifier latches are there ?
7.
What is a program card?
8.
Are additional SALs needed for the
41< to 81< section of an 81< ROS unit?
If yes, how many?
9.
What position of ROAR selects the
addresses in the 41< to 81< unit?
10.
Which position of ROAR provides the
final gate to the SAL's?
ROAR CONTROLS
•
•
•
The console lights for a ROS word
address are controlled by an indi-
cating ROAR.
The address in ROAR may be stored in
one of two J::ackup ROAR s.
Two latches are used to store backup
branch conditions.
Refer to Figure 3-40
<D.
You have seen
how an address in ROAR selects a parti-
cular ROS word.
ROAR consists of
15
polarity hold latches.
Thirteen are
used for address deCoding and two for
parity.
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