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APPENDICES
A
8192(PLS) 44
P
=
A
A
10000.0( m) 9
L
M
360448
=
90000.0
Here, reduce the above result since the A
65535.
A
45056
P
=
A
A
11250.0
L
M
Next, since the A
setting range is up to 6553.5, set 1125.0 as A
L
10 with A
.
M
A
45056(A
P
=
A
A
1125.0(A
) 10(A
L
M
L
Thus, A
, A
and A
to be set are as follows.
P
L
M
A
=45056
P
A
=1125.0
L
A
=10
M
(2) When PULSE (pulse) is set as the control unit
When using PULSE (pulse) as the control unit, set the electronic gear as
follows.
A
=number of pulses per motor revolution
P
A
=number of pulses per motor revolution
L
A
=1
M
For example, when the motor is the HC-MF (8192PLS/rev)
A
=8192
P
A
=8192
L
A
=1
M
(3) When degree is set as the control unit for a rotary axis
When the rotary axis is used, the motor is HC-SF (16384PLS/rev) and the
reduction ratio of the reduction gear is 3/11
Reduction gear 3/11
Motor
First, find how many degrees the load (machine) will travel (∆S) when the motor
turns one revolution (A
A
(number of pulses per motor revolution)
P
∆S(machine travel value per motor revolution) = 360.00000(degree)×reduction
Substitute this for the above relational expression.
At this time, make calculation with the reduction ratio 3/11 remaining as a
fraction.
setting must be made not more than
P
)
P
)
M
).
P
APP − 69
and multiply it by
L
=16384 (PLS)
=16384(PLS)×3/11
ratio
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