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Toshiba GRD150 Series Instruction Manual page 272

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6.6.2
Tripping, Reclosing and Control Circuit Test
The tripping circuit including the circuit breaker is checked by forcibly operating the output relay
and monitoring the circuit breaker to confirm that it is tripped. Forcible operation of the output
relay is performed on the "Binary O/P " screen of the "Test" sub-menu as described in Section
6.4.3.
Tripping circuit
• Set the breaker to be closed.
• Select "Binary O/P" on the "Test" sub-menu screen to display the "Binary O/P" screen.
T e s t - B i n a r y O / P
I O 1
T R P 1 : T B 3 - 1 9 , 2 0
T R P 2 : T B 4 - 1 ,
B O 1 : T B 4 - 5 ,
B O 2 : T B 4 - 7 ,
B O 3 : T B 4 - 9 , 1 0
B O 4 : T B 4 - 1 1 , 1 2
B O 5 : T B 4 - 1 3 , 1 4
2 8 F
TRP1 and TRP2 are output relays with one normally open contact.
• Enter "ENA" (Enable) for TRP1 and press the ENTER key to operate the output relay
forcibly.
• After completing the entries, press the END key to display the following confirmation
message on the bottom line.
O p e r a t e ? Y = P r e s s i n g E N T E R
• Keep pressing the ENTER (= Y) key to operate the assigned output relays. Check that the
breaker is tripped.
• Release pressing the ENTER key to reset the operation.
• Press the CANCEL key to return to the upper "Test" screen.
• Repeat for TRP2 and other BOs.
Reclosing circuit
The test is applied to Model 200s and 400s with autoreclose function.
• Ensure that the circuit breaker is open.
Select "Binary O/P" on the "Test" sub-menu screen to display the "Binary O/P" screen. The
LCD displays the output modules mounted.
Select the BO number which is an autoreclose command output relay with one normally open
contact.
Note: The autoreclose command is assigned to any of the output relays by the user setting
∗ ∗ ∗
∗ ∗ ∗
2
∗ ∗ ∗
6
∗ ∗ ∗
8
∗ ∗ ∗
∗ ∗ ∗
∗ ∗ ∗
∗ ∗ ∗
: T B 4 - 1 5 , 1 7
271
2 5 / F e b / 2 0 0 3 0 9 : 4 5
I O 2
T R P 1 : T B 5 - 1 9 , 2 0
T R P 2 : T B 6 - 1 ,
2
B O 1 : T B 6 - 5 ,
6
B O 2 : T B 6 - 7 ,
8
B O 3 : T B 6 - 9 , 1 0
B O 4 : T B 6 - 1 1 , 1 2
B O 5 : T B 6 - 1 3 , 1 4
B O 6 : T B 6 - 1 5 , 1 7
N = C A N C E L
6 F 2 S 0 8 4 2
1 / 2
∗ ∗ ∗
∗ ∗ ∗
∗ ∗ ∗
∗ ∗ ∗
∗ ∗ ∗
∗ ∗ ∗
∗ ∗ ∗
∗ ∗ ∗

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