Lightning Protection; Cable Sizing - Grundfos SP Series Installation And Operating Instructions Manual

6.3 Lightning protection

The installation can be fitted with a special overvoltage protection
device to protect the motor from voltage surges in the power
supply lines if lightning strikes somewhere in the area. See fig.
11.The installation can be fitted with a special overvoltage
protective device to protect the motor from voltage surges in the
power supply lines when lightning strikes somewhere in the area.
See fig. 11.
L1
L2
L3
PE
825045
Three-phase
Fig. 11 FittingConnecting an overvoltage protective device
The overvoltage protective device will not, however, protect the
motor against a direct stroke of lightning.
Connect Tthe overvoltage protective device
the installation as close as possible to the motor and always in
accordance with local regulations. Ask Grundfos for lightning
protective devices.
MS 402 motors, however, require no further lightning protection
as they are highly insulated.
A special cable termination kit with a built-in overvoltage
protective device is available for Grundfos 4" motors (product No
799911 or 799912).

6.4 Cable sizing

Submersible motor cables are dimensioned for
submersion in liquid, and will not necessarily have
sufficient cross-section to be in free air.
Make sure that the submersible drop cable can withstand
permanent submersion in the actual liquid and at the actual
temperature.
The cross-section (q) of the cable must meet the following
requirements:
• The submersible drop cable must be sized to the rated
maximum current of the motor.
• The cross-section must be sufficient to make a voltage drop
over the cable acceptable.
Grundfos supplies submersible drop cables for a wide range of
installations. For correct cable sizing, Grundfos offers a cable
sizing tool on the USB stick supplied with the
tool id available on Grundfos Insite at:
https://www.grundfos.com/sp-system/download-sp-app-html..
Fig. 12 Cable sizing tool
L
N
PE
825017
Single-phase
must be connected to
motorA cable sizing
The sizing tool provides an accurate calculation of the voltage
drop at a given cross-section on the basis of the following
parameters:
• cable length
• operating voltage
• full-load current
• power factor
• ambient temperature.
You can calculate tThe voltage drop
direct-on-line and star-delta starting.
In order to minimise operating losses, the cable cross-section
may be increased. This is only cost-efficient if the borehole
provides the necessary space, and if the operating time of the
pump is long. The cable sizing tool also provides a power loss
calculator that shows the potential savings of an increased
cross-section.
As an alternative to the cable sizing tool, select the cross-section
on the basis of the current values of the given cables.
The cross-section of the submersible drop cable must be large
enough to meet the voltage quality requirements specified in
section 6. Electrical connection.
Determine the voltage drop for the cross-section of the
submersible drop cable by means of the diagrams on pages
to 449.
Use the following formula:
I: rated maximum current of the motor.
For star-delta starting, I is equal to the rated maximum current of
the motor times x 0.58.
Lx: length of cable converted to a voltage drop of 1 % of the
nominal voltage.
length of drop cable
Lx =
permissible voltage drop in %
q: cross-section of submersible drop cable.
Draw a straight line between the actual I-value and the Lx-value.
Where the line intersects the q-axis, select the cross-section that
lies right above the intersection.
The diagrams are made on the basis of the formulas:
Single-phase submersible motor
L =
I × 2 × 100 ×
Three-phase submersible motor
L =
I × 1.73 × 100 ×
L Length of submersible drop cable [m]
U Rated voltage [V]
ΔU
Voltage drop [%]
I Rated maximum current of the motor [A]
cos φ 0.9
ρ Specific resistance: 0.02 [Ωmm
q Cross-section of submersible drop cable [mm
sin φ
0.436
Xl Inductive resistance: 0.078 x 10
can be calculated both for
446
U × ΔU


   
cos -- - sin
+

q
U × ΔU


   
cos -- - sin
+

q
2
/m]
2
]
-3
[Ω/m].

XI


XI

13