Calculation Example For Response Time - Mitsubishi Electric MELSEC iQ-R Series Safety Manual

Calculation example for response time

The following shows calculation examples.
• Safety cycle time of the Safety CPU (1): 3ms (SCcpu)
• Safety cycle time of the Safety CPU (2): 3ms (SCcpu)
• Input response time of the safety remote I/O module: 1.4ms (SRin)
• Output response time of the safety remote I/O module: 0.4ms (SRout)
• Safety remote station refresh response processing time: 2ms
Calculation example of CC-Link IE Field Network transmission time
Calculation example of CC-Link IE Field Network transmission time
■Calculation example of the link scan time (LS) of the CC-Link IE Field Network
Link scan time (LS) is used for calculation of the CC-Link IE Field Network transmission time. The following shows calculation
example of network number 1 (Condition: No communication error station exists.)
For Ka to Ke, use values when the station is set to normal mode.
For network number 1, the total number of set points of RX and RY becomes 256, while the total number of set points of RWr
and RWw becomes 320.
Set transient transmission and switching hub to not used, and set submaster station to not set.
LS = [{(Total number of set points for RX and RY)  4 + (Total number of set points for RWr and RWw)  4}  0.08 + (Number
of slave stations actually connected  Ka) + Kb + Kc + Kd] 1000 + (Number of interrupt conditions in the interrupt setting) 
0.02 + (Total Ke of each unit)  1000 + St [ms]
= {(256  4 + 320  4)  0.08 + (2  25.8) + 655 + 0 + 0}  1000 + 0  0.02 + (33.6 + 19.7)  1000 + 0
0.85 [ms]
The following shows a calculation example for network number 2 and 3. (Condition: No communication error station exists.)
For Ka to Ke, use values when the station is set to normal mode.
For network number 2 and 3, the total number of set points of RX and RY becomes 128, while the total number of set points of
RWr and RWw becomes 160
Set transient transmission and switching hub to not used, and set submaster station to not set.
LS (2) = LS (3) = [{(Total number of set points of RX and RY)  4 + (Total number of set points of RWr and RWw)  4}  0.08 +
(Number slave stations actually connected  Ka) + Kb + Kc + Kd]  1000 + (Number of interrupt conditions in the interrupt
setting)  0.02 + (Total Ke of each unit)  1000 + St [ms]
= {(128  4 + 160  4)  0.08 + (1  25.8) + 655 + 0 + 0}  1000 + 0  0.02 + 37.4  1000 + 0  0.78 [ms]
APPX
244
Appendix 2 Calculating Safety Response Time for System Connected to Multiple Safety CPUs