Galil Motion Control DMC-18 2 Series User Manual page 177

K f = 4N/2π = 636
ZOH
H(s) = 2000/(s+2000)
Compensation Filter
G(s) = P + sD
The next step is to combine all the system elements, with the exception of G(s), into one function, L(s).
L(s) = M(s) K a K d K f H(s) =3.17∗10 6 /[s 2 (s+2000)]
Then the open loop transfer function, A(s), is
A(s) = L(s) G(s)
Now, determine the magnitude and phase of L(s) at the frequency ω c = 500.
L(j500) = 3.17∗10 6 /[(j500) 2 (j500+2000)]
This function has a magnitude of
|L(j500)| = 0.00625
and a phase
Arg[L(j500)] = -180° - tan -1 (500/2000) = -194°
G(s) is selected so that A(s) has a crossover frequency of 500 rad/s and a phase margin of 45 degrees.
This requires that
|A(j500)| = 1
Arg [A(j500)] = -135°
However, since
A(s) = L(s) G(s)
then it follows that G(s) must have magnitude of
|G(j500)| = |A(j500)/L(j500)| = 160
and a phase
arg [G(j500)] = arg [A(j500)] - arg [L(j500)] = -135° + 194° = 59°
In other words, we need to select a filter function G(s) of the form
G(s) = P + sD
so that at the frequency ω c =500, the function would have a magnitude of 160 and a phase lead of 59
degrees.
These requirements may be expressed as:
|G(j500)| = |P + (j500D)| = 160
and
arg [G(j500)] = tan -1 [500D/P] = 59°
The solution of these equations leads to:
P = 160cos 59° = 82.4
500D = 160sin 59° = 137
166 ● Chapter 10 Theory of Operation
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DMC-18x2