STMicroelectronics STM32F050G6 Manual page 94

Low- and medium-density advanced arm-based 32-bit mcu with up to 32 kbytes flash, timers, adc and comm. interfaces
Table of Contents

Advertisement

Package characteristics
The following examples show how to calculate the temperature range needed for a given
application.
Example 1: High-performance application
Assuming the following application conditions:
Maximum ambient temperature T
I
DDmax
level with I
at low level with I
P
INTmax
P
IOmax
This gives: P
P
Dmax
Using the values obtained in
T
Jmax
This is within the range of the suffix 6 version parts (–40 < T
General operating conditions on page
In this case, parts must be ordered at least with the temperature range suffix 6 (see
Section 8: Part
Note:
With this given P
(order code suffix 6 or 7).
Suffix 6: T
Suffix 7: T
Example 2: High-temperature application
Using the same rules, it is possible to address applications that run at high ambient
temperatures with a low dissipation, as long as junction temperature T
specified range.
Assuming the following application conditions:
Maximum ambient temperature T
I
DDmax
level with I
P
INTmax
P
IOmax
This gives: P
P
Dmax
Thus: P
Dmax
Using the values obtained in
T
Jmax
This is above the range of the suffix 6 version parts (–40 < T
94/98
= 50 mA, V
= 3.5 V, maximum 20 I/Os used at the same time in output at low
DD
= 8 mA, V
= 0.4 V and maximum 8 I/Os used at the same time in output
OL
OL
= 20 mA, V
OL
= 50 mA × 3.5 V= 175 mW
= 20 × 8 mA × 0.4 V + 8 × 20 mA × 1.3 V = 272 mW
= 175 mW and P
INTmax
= 175 + 272 = 447 mW
Table 66
For LQFP48, 55 °C/W
= 80 °C + (55°C/W × 447 mW) = 80 °C + 24.585 °C = 104.585 °C
numbering).
we can find the T
Dmax
= T
- (55°C/W × 447 mW) = 105-24.585 = 80.415 °C
Amax
Jmax
= T
- (55°C/W × 447 mW) = 125-24.585 = 100.415 °C
Amax
Jmax
= 20 mA, V
= 3.5 V, maximum 20 I/Os used at the same time in output at low
DD
= 8 mA, V
= 0.4 V
OL
OL
= 20 mA × 3.5 V= 70 mW
= 20 × 8 mA × 0.4 V = 64 mW
= 70 mW and P
INTmax
= 70 + 64 = 134 mW
= 134 mW
Table 66
For LQFP48, 55 °C/W
= 100 °C + (55 °C/W × 134 mW) = 100 °C + 7.37 °C = 107.37 °C
Doc ID 023079 Rev 3
= 80 °C (measured according to JESD51-2),
Amax
= 1.3 V
OL
= 272 mW:
IOmax
T
is calculated as follows:
Jmax
39.
allowed for a given device temperature range
Amax
= 100 °C (measured according to JESD51-2),
Amax
= 64 mW:
IOmax
T
is calculated as follows:
Jmax
STM32F050xx
< 105 °C) see
Table 15:
J
remains within the
J
< 105 °C).
J

Advertisement

Table of Contents
loading
Need help?

Need help?

Do you have a question about the STM32F050G6 and is the answer not in the manual?

Subscribe to Our Youtube Channel

Table of Contents