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Section 10
Testing functionality by secondary injection
134
frequency of V
= 50 Hz
ts
I
CTs
10459
I
I
=
×
=
50
s
50
I
CTp
EQUATION14059 V1 EN
∠I
= 0º
50s
frequency of I
= 50 Hz
50s
I
It
I
CTs
10459
=
×
=
tf
fs
I
CTp
EQUATION14062 V1 EN
∠I
= 0º
tfs
frequency of I
= 50 Hz
tfs
•
Check that the service values (VOLTAGE, CURRENT, R(%), X(%)) are
according to the injected quantities and that ROTORANG is close to 3.14 rad. For
this particular injection the service values are:
•
VOLTAGE = 1.58 kV
•
CURRENT = 20918 A
•
R = 1.08%
•
X = 7.85%
•
ROTORANG = -3.04 rad
Note that these values identify a point inside the lens characteristic, in the Zone 2, that
is close to the boundary between zone 1 and zone 2. The START is issued, but no TRIP
is performed.
Execution of the dynamic test
The test may be performed by using two states of a sequence tool that is a basic feature
of test sets.
•
State 1: pre-test condition.
Steady voltage and current are applied in order to get a steady high impedance,
that is a point in the plane R-X that is far away from the lens characteristic. Define
the following three-phase symmetrical quantities (the phase angle is related to
phase L1):
V
VT s
,
V
1 1
.
V
=
×
×
ts
t RZ
,
1
V
VT p
,
EQUATION14065 V1 EN
ForwardX
∠
=
V
arctan
ts
ForwardR
EQUATION14058 V1 EN
frequency of V
= 50 Hz.
t
I
= 0 A
50s
1
= .
1 162
A
×
9000
1
1 162
.
A
×
=
9000
0 1
.
1 1 1435
.
11 44
.
=
×
×
=
13 8
.
59 33
.
=
=
arctan
82. . 14°
8 19
.
1MRK 506 355-UEN A
V
Line distance protection REL670 2.1 IEC
Commissioning manual
(Equation 39)
(Equation 40)
(Equation 41)
(Equation 42)
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