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Section 10
Testing functionality by secondary injection
132
I
CTs
I
I
10459
=
×
=
50
s
50
I
CTp
EQUATION14059 V1 EN
∠I
= 0º
50s
frequency of I
= 50 Hz
50s
I
CTs
10459
It
I
=
×
=
tf
fs
I
CTp
EQUATION14062 V1 EN
∠I
= 0º
tfs
frequency of I
= 50 Hz
tf
•
Check that the service values (VOLTAGE, CURRENT, R(%), X(%) ) are
according to the injected quantities and that ROTORANG is close to 3.14 rad. For
this particular injection the service values are:
•
VOLTAGE = 10.74 kV
•
CURRENT = 20918 A
•
R = 7.37%
•
X = 53.40%
•
ROTORANG = -3.09 rad
Note that these values identify a point inside the lens characteristic, in the zone 2,
that is close to the point RE. The START is issued, but no TRIP is performed.
Execution of the dynamic test
The test may be performed by using two states of a sequence tool that is a basic feature
of test sets.
•
State 1: pre-test condition.
Steady voltage and current are applied in order to get a steady high impedance,
that is, a point in the plane R-X which is far away from the lens characteristic.
Define the following three-phase symmetrical quantities (the phase angle is
related to phase L1):
V
VT s
V
0 9
.
V
=
×
×
ts
t FwdZ
,
V
VT p
EQUATION14063 V1 EN
ForwardX
∠
=
V
arctan
ts
ForwardR
EQUATION14058 V1 EN
frequency of V
= 50 Hz
ts
I
= 0 A
50s
I
= 0 A
tfs
•
State 2: main test step.
1
= .
1 162
A
×
9000
1
1 162
.
A
×
=
9000
0 1
.
,
0 9 11931
.
77 81
=
×
×
=
13 8
.
,
59 33
.
=
=
arctan
8 19
.
1MRK 506 355-UEN A
.
V
82. . 14°
Line distance protection REL670 2.1 IEC
Commissioning manual
(Equation 29)
(Equation 30)
(Equation 31)
(Equation 32)
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