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Section 10
Testing functionality by secondary injection
130
I
CTs
I
I
10459
=
×
=
50
s
50
I
CTp
EQUATION14059 V1 EN
∠I
=0°
50s
frequency of I
= 50 Hz
50s
I
CTs
10459
It
I
=
×
=
tf
fs
I
CTp
EQUATION14062 V1 EN
∠I
=0°
tfs
frequency of I
= 50 Hz
tfs
•
Check that the service values (VOLTAGE, CURRENT, R(%), X(%)) are
according to the injected quantities and that ROTORANG is close to 0 rad.
For this particular injection the service values are:
•
VOLTAGE = 13.12 kV
•
CURRENT = 20918 A
•
R = 9.01%
•
X = 65.27%
•
ROTORANG = 0.04 rad
Note that these values identify a point outside the lens characteristic, even if it is close
to the point RE. Neither START nor TRIP is issued.
Execution of the dynamic test
The test may be performed by using two states of a sequence tool that is a basic feature
of test sets.
•
State 1: pre-test condition.
Steady voltage and current are applied in order to get a steady high impedance.
This is a point in the plane R-X that is far away from the lens characteristic. Define
the following three-phase symmetrical quantities (the phase angle is related to
phase L1):
V
VT s
,
V
1 1
.
V
=
×
×
,
ts
t FwdZ
V
VT p
,
EQUATION14057 V1 EN
ForwardX
∠
=
arctan
V
ts
ForwardR
EQUATION14058 V1 EN
frequency of V
= 50 Hz
ts
I
=0 A
50s
I
=0 A
tfs
•
State 2: main test step.
1
= .
1 162
A
×
9000
1
1 162
.
A
×
=
9000
0 1
.
1 1 11931
.
95 1
.
=
×
×
=
13 8
.
59 33
.
=
=
arctan
82. . 14°
8 19
.
1MRK 506 355-UEN A
V
Line distance protection REL670 2.1 IEC
Commissioning manual
(Equation 19)
(Equation 20)
(Equation 21)
(Equation 22)
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