Selecting The Product Temperature Range - STMicroelectronics STM32F038C6 Manual

Arm-based 32-bit mcu with 32 kbyte flash, 9 timers, adc and communication interfaces, 1.8 v
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7.6.2

Selecting the product temperature range

When ordering the microcontroller, the temperature range is specified in the ordering
information scheme shown in
Each temperature range suffix corresponds to a specific guaranteed ambient temperature at
maximum dissipation and, to a specific maximum junction temperature.
As applications do not commonly use the STM32F038x6 at maximum dissipation, it is useful
to calculate the exact power consumption and junction temperature to determine which
temperature range will be best suited to the application.
The following examples show how to calculate the temperature range needed for a given
application.
Example 1: High-performance application
Assuming the following application conditions:
Maximum ambient temperature T
I
DDmax
level with I
at low level with I
P
INTmax =
P
IOmax = 20
This gives: P
P
Dmax =
Using the values obtained in
T
Jmax
This is within the range of the suffix 6 version parts (–40 < T
General operating
In this case, parts must be ordered at least with the temperature range suffix 6 (see
Section 8: Part
Note:
With this given P
6 or 7).
Suffix 6: T
Suffix 7: T
Example 2: High-temperature application
Using the same rules, it is possible to address applications that run at high ambient
temperatures with a low dissipation, as long as junction temperature T
specified range.
96/102
Section 8: Part
= 50 mA, V
= 3.5 V, maximum 20 I/Os used at the same time in output at low
DD
= 8 mA, V
= 0.4 V and maximum 8 I/Os used at the same time in output
OL
OL
= 20 mA, V
OL
50 mA × 3.5 V= 175 mW
× 8 mA × 0.4 V + 8 × 20 mA × 1.3 V = 272 mW
= 175 mW and P
INTmax
175
272 = 447 mW
+
Table 66
For LQFP48, 55 °C/W
= 80 °C + (55°C/W × 447 mW) = 80 °C + 24.585 °C = 104.585 °C
conditions.
numbering).
Dmax we can find the TAmax allowed for a given device temperature range (order code suffix
= T
- (55°C/W × 447 mW) = 105-24.585 = 80.415 °C
Amax
Jmax
= T
- (55°C/W × 447 mW) = 125-24.585 = 100.415 °C
Amax
Jmax
DocID026079 Rev 3
numbering.
= 80 °C (measured according to JESD51-2),
Amax
= 1.3 V
OL
= 272 mW:
IOmax
T
is calculated as follows:
Jmax
STM32F038x6
< 105 °C) see
Table 18:
J
remains within the
J

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