Omron CS1W-LC001 Operation Manual page 122

Description of Operation
Example
104
Total operation execution time of function block at 0.5 sec operation cycle
(ms) + 10 ms = T5,
Total operation execution time of function block at 1 sec operation cycle (ms)
+ 10 ms = T10,
Total operation execution time of function block at 2 sec operation cycle (ms)
+ 10 ms = T20
Operation cycle
0.1 sec.
0.2 sec.
0.5 sec.
1 sec.
2 sec.
Where
T1 (total operation execution time of function block at 0.1 sec operation cycle)
+ 10 ms = 20 ms, T2 (total operation execution time of function block at 0.2
sec operation cycle) + 10 ms = 30 ms, T5 (total operation execution time of
function block at 0.5 sec operation cycle) + 10 ms = 60 ms, T10 (total
operation execution time of function block at 1 sec operation cycle) + 10 ms =
110 ms and T20 (total operation execution time of function block at 2 sec
operation cycle) + 10 ms = 40 ms
Operation cycle
0.1 sec.
0.2 sec.
0.5 sec.
1 sec.
2 sec.
Procedure 2: The load rate of each operation cycle is calculated by the
formula below.
Formula:
Load rate of each operation cycle = Total operation execution time (ms) of
each function block above Á operation cycle (ms) x 100
The load rate of each operation cycle must be 60% or less.
Total operation execution time of each function block
T1
Á
Where T2 100 ms = A, (integer part of A) x T1 + T2
Á
Where T5 100 ms = A and T5
of A) x T1 + (integer part of B) x T2 + T5
Á
Where T10 100 ms = A, T10
500 ms = C, (integer part of A) x T1 + (integer part of B) x
T2 + (integer part of C) x T5 + T10
Á
Where T20 100 ms = A, T20
Á
= C, and T20 1000 ms = D, (integer part of A) x T1 +
(integer part of B) x T2 + (integer part of C) x T5 + (integer
part of D) x T10 + T20
Total operation execution time of each function block
20 ms
Á
As 30 ms 100 ms = 0.3 (A),
0 (integer part of A) x 20 ms + 30 ms = 30 ms
Á
As 60 ms 100 ms = 0.6 (A), and 60 ms
(B),
0 (integer part of A) x 20 ms + 0 (integer part of B) x 30 ms
+ 60 ms = 60 ms
Á
As 110 ms 100 ms = 1.1 (A), 110 ms
Á
and 110 ms 500 ms = 0.22 (C),
1 (integer part of A) x 20 ms + 0 (integer part of B) x 30 ms
+ 0 (integer part of C) x 60 ms + 110 ms = 130 ms
Á
As 40 ms 100 ms = 0.4 (A), 40 ms
Á
ms 500 ms = 0.08 (C), and 40 ms
0 (integer part of A) x 20 ms + 0 (integer part of B) x 30 ms
+ 0 (integer part of C) x 60 ms + 0 (integer part of D) x
110 ms + 40 ms = 40 ms
Section 3-2
Á
200 ms = B, (integer part
Á Á
200 ms = B, and T10
Á Á
200 ms = B, T20 500 ms
Á
200 ms = 0.3
Á
200 ms = 0.55 (B),
Á
200 ms = 0.2 (B), 40
Á
1000 ms = 0.04 (D),