Omron TJ2-MC64 - PROGRAMMING Programming Manual page 274

Examples and tips
The evident solution is: n = 100 and m = 1224. Or, when we simplify the
factors: n = 25 and m = 306. Therefore: Pn205 = m – 1 = 305. With these
settings, executing MOVE(180) moves the moving part 180 tenths of an
angle degree or 18 angle degrees in forward direction.
Example 5
The mechanical system uses a servo motor with a 17-bit absolute encoder.
The mechanical gear ratio of the gearbox is 1:10. The pulley has got 12
teeth, and each two are 50 mm apart. One complete turn of the pulley
equals 144 stations on the main wheel. The distance between two stations is
50 mm. The mechanical measurement units must mm. Total repeat distance
must be the distance between two stations, 50mm.
With the same procedure as in example 1, we have:
Pn202
UNITS =
Pn203
17
. .
2 encoder_counts 10 motor_revolution
.
. .
1 motor_revolution 1 pulley_revolution
17
.
2 10 encoder_counts
=
.
12 50 mm
Therefore, if we use the mechanical system to set the electronic gear ratio,
we have:
UNITS
One possible solution is:
PROGRAMMING MANUAL
. .
1 pulley_revolution 1 station
.
.
12 station 50mm
17
Pn202 2 10
=
Pn203 50 12
17
2
UNITS =
50
Pn202 = 5
Pn203 = 6
Pn205 = 4
M
17-bit absolute 1:10 Gear
encoder
Pulley: 12 teeth
50mm between teeth
=
fig. 23
Main Wheel: 144 stations
50 mm between stations
268