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If the start position is raised, S=-90. For the level position, S=0, or S= (S=0 is
equivalent to S=).
Level
S=0
After the start position, we have to specify the details for the first position,
as follows:
{Number of position until the changes occur}
={upper rotator position}_{lower rotator position}
1=0_0
1
Next 1st position for the change to occur
=0
Upper rotator at a tilt or pitch of 0° (thus it does not move)
Lower rotator at a yaw of 0° relative to the previous (thus it does
_0
not move)
Assuming parked position, our script becomes:
S=90, 1=0_0,
Then we have to think about how we want the rotators to move so that we
have 12 photos around, 30° apart.
For the next position, the lower rotator rotation will be 30°, while for the
upper rotator the position does not change.
We can write that as 1=0_30, but S language also allows this compact form
instead:
=_30,
by omitting the number 1, and writing the equal sign followed
by nothing, meaning no changes for the upper rotator.
So, the script becomes:
S=90, 1=0_0, =_30,
The movement for the next 10 positions or photos (as we have only one
photo at every position) will continue by changing only the rotation of the
lower rotator, then at 11th photo something changes, the upper rotator
should rotate the upper rail up 45°, so we have to add
MECHA C2 User's Guide v.02.5
Parked
Raised
S=90
S=-90
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Other
S=45
11=45,
to our script:
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