Rated resist-
Device
Technology
ance R
BR
G394-059
100 Ω
G394-035
420 Ω
G394-080
90 Ω
G394-065
Wire resistance
G394-120
90 Ω
G394-160
90 Ω
1) Data referred to 1 x 230 V AC mains voltage (BR switch-on threshold 390 V DC)
2) Data referred to 3 x 400 V AC mains voltage (BR switch-on threshold 650 V DC)
3) Data referred to 3 x 460 V AC mains voltage (BR switch-on threshold 745 V DC)
4) Data referred to 3 x 480 V AC mains voltage (BR switch-on threshold 765 V DC)
K1 = Factor for the calculation of the permissible continuous braking power, see next page
Table 4.16 Data of the integrated braking resistor (design G394-xxx-xxx-xx2/xx4)
If the drive is not permanently operated at its power limit, the reduced power dissipation
of the drive can be used as braking power.
NOTE:
The rest of the calculation assumes that the servo drive is used at maximum
permissible ambient temperature. This means that any additional energy input
for the internal braking resistor due to a lower ambient temperature will be
neglected.
moog
ID no.: CA97555-001 Date: 04/2018
Peak braking
Pulse
K1
power P
energy W
PBr
IBr
1500 W
150 Ws
120
1)
1000 W
2)
1300 W
140 Ws
50
3)
1400 W
4)
1690 W
6000 Ws
170
1)
4700 W
2)
6170 W
6000 Ws
120
3)
6500 W
4)
4700 W
2)
6170 W
6000 Ws
120
3)
6500 W
4)
4700 W
2)
6170 W
6000 Ws
120
3)
6500 W
4)
Method to calculate the continuous braking power:
Calculation of effective servo drive utilisation in
y
a cycle T:
y
Determination of permissible continuous braking
power based on unused drive power:
Marginal conditions
y
A single braking action must not exceed the
maximum pulse energy of the braking resistor.
The continuous braking power calculated for the
y
device must be greater than the effective braking
power of a device cycle.
This results in the minimum permissible
cycle time T with calculated continuous
braking power:
The maximum total on-time of the braking
resistor over a specified cycle time T with
calculated continuous braking power is:
MSD Single-Axis Servo Drive Compact Operation Manual
T
1
T
∫
I
=
i
2
dt
1
T
1
∫
eff
T
I
i
2
dt
=
∫
I
=
i
2
dt
eff
T
0
eff
T
0
T
0
1
∫
I
=
i
2
dt
eff
T
T
1
I
∫
eff
P
2
K
I
=
=
1
−
I
0
i
dt
×
1
I
DBr
eff
eff
T
I
P
=
1
−
×
K
1
eff
P
K
=
1
−
×
1
N
DBr
I
0
DBr
I
N
N
I
eff
P
=
1
−
×
K
1
DBr
T
1
I
I
∫
N
P
≥
×
T
P
dt
1
eff
P
=
1
−
×
K
1
T
1
∫
DBr
PBr
Br
P
≥
T
×
P
dt
DBr
I
∫
W
≥ P
x T
P
≥
×
P
dt
DBr
PBr
Br
0
T
N
IBr
PBr
Br
DBr
PBr
Br
T
0
0
T
1
∫
P
≥
×
P
dt
DBr
PBr
Br
T
T
1
T
P
∫
0
P
≥
×
P
dt
∫
T
=
PBr
×
T
dt
P
DBr
PBr
Br
T
T
P
∫
Br
T
=
P
PBr
×
dt
∫
T
=
PBr
0
×
dt
DBr
Br
0
P
Br
P
DBr
0
DBr
0
T
P
∫
T
=
PBr
×
dt
Br
P
P
T
DBr
0
∫
T
dt
=
PBr
×
Br
P
P
DBr
0
T
=
PBr
×
T
P
P
BrSum
T
=
P
PBr
×
T
T
=
PBr
×
T
BrSum
DBr
P
BrSum
P
DBr
DBr
P
T
=
PBr
×
T
BrSum
P
P
DBr
T
T
=
PBr
×
BrSum
P
DBr
41
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