Table of Contents
Advertisement
Starting up the FM 453
MD54: Start/stop frequency f
1. Enter J
into J diagram (e.g. 3 kg
Load
2. Determine f0 (e.g. 150 Hz) from intersection
with J curve
3. Shift base point of SS curve to f0
MD56: Maximum frequency f
1. Enter maximum frequency f
2. Enter MD56 = f
max
Read available motor torque M2 at f
No
Compare torque M2 with the idle time torque M0 of
Parameterize the speed
profile by way of simple
ramp
Enter
MD55 = MD56
MD58 = 0
MD60 = 0
Equate acceleration element for all f --
f
: M
= M
max
b1
b2
MD60: Delay 2 a
v2
E.g. technological concerns may make a certain delay desirable, or friction torque
factors may provide a torque which deviates from the acceleration case. MD60 must
be either be calculated along the lines of the formula used to calculate MD58, or some
technologically desirable value must be verified.
MD58: Acceleration 2 a
b2
1. Acceleration torque M
b2
2. Calculate delay:
3. 20% certainty: a
= 0.8
b2
4. Enter rounded off value per MD 58
Acceleration element M
Yes
Should values for acceleration and delay be
MD59: Delay 1 a
Enter
E.g. technological concerns may make a certain delay desirable, or friction torque
MD59 = 0
factors may provide a torque which deviates from the acceleration case. MD59 must
be either be calculated along the lines of the formula used to calculate MD57, or some
technologically desirable value must to be verified.
MD57: Acceleration 1 a
1. Calculate delay:
2. 20% certainty: a
3. Enter rounded off value per MD 57
Fig. 7-6
Evaluation of Operating Characteristic Curves
7-16
ss
2
cm
)
4. Enter M
5. Determine f1 (e.g. 130 Hz) from intersection
6. Enter MD54 = f
max
(e.g. 10,000 Hz) into the M diagram at maximum axis speed
max
(e.g. 1.8 Nm)
max
the stepper motor: M2<< M0?
MD40: Frequency value for acceleration switchover f
1. Enter M1 = 2
2. Read f
(e.g. 3,000 Hz) from frequency scale
eg
3. Enter MD55 = f
No
Should values for acceleration and delay be
(e.g. 1.2 Nm)
10,000
M
[Nm]
b2
a [Hz] =
2
J
[kg cm
]
total
a
(e.g. 109,134 Hz/sec)
(e.g. 109,000 Hz/sec)
determined (e.g. 2.4 Nm)
b1
identical within the range f < f
eg
v1
b1
a [Hz] =
= 0.8 a
b1
in M diagram (e.g. 0.6 Nm)
Load
with SS curve
= 0.8
f1 (e.g. 104 Hz)
ss
yes (e.g. 1.8 << 5)
Parameterize the speed
profile by way of bent
ramp
M2 - M
into M diagram (e.g. 3 Nm)
Load
eg
identical within the range f > f
?
eg
MD13
(e.g. 136 418 Hz)
2 π
No
?
MD13
10,000
M
[Nm]
b1
] 2 π
2
J
[kg cm
total
(e.g. 218,269 Hz)
(e.g. 218,000 Hz/s)
END
FM 453 Servo Drive / Step Drive Positioning Module
C79000-G7076-C453-01
eg
Yes
Enter
MD60 = 0
J
= J
+ J
total
Motor
Load
2
J
= 7 kg cm
total
(e. g. 272 837 Hz)
Advertisement
Table of Contents
