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S5-95F
Conditions for the SINEC L1 Safety Time for Receive
1st condition
The following condition requires consideration of the transmitting and the receiving system.
The receiving S5-95F must fulfill the following as regards the SINEC L1 safety time:
SINEC L1 safety time for Receive
k= Number of failsafe Send paths used by the S5-95F (k=1 or 2) or S5-115F (k=1 to 30), where:
k=1
for one failsafe data path
k=2 to 30
for 2 to 30 failsafe data paths (the data path to the master must also be included
in the case of the S5-115F)
l= Factor for non-failsafe data traffic, where
l=0,
when the relevant transmitter sends non-failsafe data only rarely or not at all
l=1,
when the relevant transmitter sends non-failsafe data frequently
n= Number of times the relevant transmitter is polled in the polling list
If polled more than once, the node number must be evenly distributed throughout the list, e.g.:
1 2 3 4 2 5 6 2 7 8 2 9
SINEC L1 bus cycle time =
TIP:
You can reduce the SINEC L1 bus cycle time by specifying smaller amounts of data and/or
fewer data paths in the polling list.
2nd condition
The time between two successive frames from the master to a given slave must be
SINEC L1 safety time for Receive.
3rd condition (for double SINEC L1 bus only)
When a given S5-95F receives frames from the master and a double SINEC L1 bus is being used,
the following condition must be fulfilled:
SINEC L1 safety time for Receive SINEC L1 safety time for Send + 500 ms
The formula for computing the SINEC L1 safety time for Send can be found in section 18.19.2.
EWA 4NEB 812 6210-02
2·(k+l)·SINEC L1 bus cycle time
Number of frame bytes (plus 4 bytes in the case of failsafe
frames)×2 ms
+
Number
of
failsafe
network×44 ms
Rules for Failsafe Operation of an S5-95F
n
data
paths
in
the
+200 ms
entire
SINEC
L1
1.5 x slave's
18-39
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