Pentek 6230 Operating Manual page 90

AD6644–SPECIFICATIONS
Parameter
5
DATA READY (DRY )/DATA, OVR
Data Ready to DATA Delay (Hold Time)
Encode = 65 MSPS (50% Duty Cycle)
Encode = 40 MSPS (50% Duty Cycle)
Data Ready to DATA Delay (Setup Time)
@ 65 MSPS (50% Duty Cycle)
@ 40 MSPS (50% Duty Cycle)
APERTURE DELAY
APERTURE UNCERTAINTY (JITTER)
NOTES
1
Several timing parameters are a function of t
2
To compensate for a change in duty cycle for t
Newt = (t – % Change(t
H_DR H_DR ENCH
Newt = (t – % Change(t
S_DR S_DR ENCH
3
ENCODE to DATA Delay (Hold Time) is the absolute minimum propagation delay through the analog-to-digital converter.
4
ENCODE to DATA Delay (Setup Time) is calculated relative to 65 MSPS (50% duty cycle). In order to calculate t
Newt = t – t + t (i.e., for 40 MSPS: Newt
S_E ENC(NEW) ENC S_E
5
DRY is an inverted and delayed version of the encode clock. Any change in the duty cycle of the clock will correspondingly change the duty cycle of DRY.
6
Data Ready to DATA Delay(t
H_DR
and t for a given encode use the following equations:
S_DR
Newt = t /2 – t + t
H_DR ENC(NEW) ENCH
Newt = t /2 – t + t
S_DR ENC(NEW) ENCH
Specifications subject to change without notice.
t
A
N
AIN
ENC, ENC
N
t
E_FL
t
E_RL
D[13:0], OVR
DRY
Name
2
t
H_DR
2
t
S_DR
t
A
t
J
and t .
ENC ENCH
and t use the following equation:
H_DR S_DR
)) × t
/2
ENC
)) × t
/2.
ENC
= 25 × 10
S_E(TYP)
and t ) is calculated relative to 65 MSPS (50% duty cycle) and is dependent on t
S_DR
(i.e., for 40 MSPS: Newt
H_DR H_DR(TYP)
(i.e., for 40 MSPS: Newt
S_DR S_DR(TYP)
N 1
t t
ENC ENCH
N 1
N–3
Figure 1. Timing Diagram
Test
Temp Level
Full IV
Full IV
Full IV
Full IV
25°C V
25°C V
– 15.38 × 10 + 9.8 × 10 = 19.4 × 10
–9 –9 –9
= 12.5 × 10 – 7.69 × 10 + 8.6 × 10
–9 –9
= 12.5 × 10 – 7.69 × 10 + 5.5 × 10
–9 –9
N 2
t
ENCL
N 2
t
E_DR
N–2 N–1
t
t
S_DR
DR
–4–
AD6644AST-40/65
Min Typ Max
Note 6
8.0 8.6 9.4
12.8 13.4 14.2
Note 6
3.2 5.5 6.5
8.0 10.3 11.3
100
0.2
for a given encode use the following equation:
S_E
–9
).
and duty cycle. In order to calculate t
ENC
= 13.4 × 10
–9 –9
= 10.3 × 10
–9 –9
.
N 3
N 4
N 3
t
t
S_E
N
t
H_DR
Unit
ns
ns
ns
ns
ps
ps rms
H_DR
N 4
H_E
REV. 0