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General Information on AC Induction Motors
3 Planning
ALA
ALA/3-26
Calculating the accelerating torques
J<∆n
M
=
B
9.55<t
a
Accelerating for 1 s from 0 to 2000 RPM:
0.2<2000
Nm = 41.8 Nm 42 Nm
M
=
B
9.55<1
Braking for 1 s from 2000 to 1500 RPM:
0.2<(–500)
M
=
= –10.5 Nm
B
9.55<1
Braking for 2.5 s from 1500 to 0 RPM:
0.2<(–1500)
M
=
= –12.6 Nm
B
9.55<2.5
Maximum torque M
: 42 Nm for 1 s
max
Calculating the RMS motor torque in the operating cycle (duty cycle)
2
2
M
t
+ M
t
+...+ M
1<
1
2<
2
M
=
rms
T
2 <
<1 + 36
2
42
120 + 30
M
=
rms
= 24.7 Nm 25 Nm
M
rms
Motor selection:
With the data:
Speed
Maximum motor torque M
RMS motor torque:
a motor with n
= 2000 RPM, M
n
is selected from the torque characteristics.
Drive converter selection
From the power–speed diagram:
The power at rated speed and 42 Nm maximum torque should be entered. The
current requirement can be determined from the characteristics.
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2
t
n<
n
<60 + (–10.5)
<60 + (–12.6)
2
2
2
1<1 + 36
474.5
:
max
w 25 Nm
n
SIMODRIVE Planning Guide Motors (PJM) – 11.00 Edition
09.00
<2.5
2
2000 RPM
42 Nm
25 Nm
6SN1197–0AA20
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