Communication
Calculation example 1
Calculation example 2
Calculation example 3
156
Ttx = sending time per byte
Tso = master station scan time
Conditions: All stations have been added to a 16-unit link. Highest station
number = 16. Flags and registers have been evenly allocated. Scan time
for each PLC: 1ms.
Ttx = 0.096
Pcm (per station) = 23 + (4 + 8) 4 = 71
Tpc = Ttx Pcm = 0.096 71 6.82ms
Ts (per station) = 1 + 6.82 = 7.82ms
Tlt = 0.096 (13 + 2 16) = 4.32ms
Given the above conditions, the maximum value for the transmission time
(T) of one cycle will be: T max. = 7.82 16 + 4.32 + 1 = 130.44ms
Conditions: All stations have been added to a 16-unit link. Highest station
number = 16. Flags and registers have been evenly allocated. Scan time
for each PLC: 5ms.
Ttx = 0.096
Pcm (per station) = 23 + (4 + 8) 4 = 71
Tpc = Ttx Pcm = 0.096 71 6.82ms
Ts (per station) = 5 + 6.82 = 11.82ms
Tlt = 0.096 (13 + 2 16) = 4.32ms
Given the above conditions, the maximum value for the transmission time
(T) of one cycle will be: T max. = 11.82 16 + 4.32 + 5 = 198.44ms
Conditions: All but one station have been added to a 16-unit link. Highest
station number = 16. Flags and registers have been evenly allocated. Scan
time for each PLC: 5ms.
Ttx = 0.096
Ts (per station) = 5 + 6.82 = 11.82ms
Tlt = 0.096 (13 + 2 15) = 4.31ms
Tlk = 0.96 + 400 + 0.67 + 5 407ms
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