Table 16: Component Power Requirements - Juniper Internet Router M160 Hardware Manual

M160 Internet Router Hardware Guide

Table 16: Component Power Requirements

Component
Base system (cooling system, power supplies, and craft
interface)
Host module (Routing Engine and MCS)
FPC
PCG
SFM
You can use the information in Table 16 and the M160 Internet Router PIC
Guide to calculate power consumption for various hardware configurations,
input current from a different source voltage, and thermal output, as shown
in the following examples. (For an added safety margin, the examples use
a generalized value for PICs of 0.625 A/48 V each.)
NOTE: If you plan to operate a maximally configured router, we recommend that
you provision at least 70 A @ 48 VDC and use a facility circuit breaker rated for
70 A minimum. Doing so enables you to operate the router in any configuration
without upgrading the power infrastructure, and allows the router to function at
full capacity using one power supply.
If you plan to operate the router at less than the maximum configuration and do not
provision a 70 A circuit breaker, we recommend that you provision a circuit breaker
rated for at least 125% of the continuous current that the system draws at 48 V.
66
Power Guidelines, Requirements, and Specifications
Power consumption for minimum configuration:
Base system + 1 FPC + 1 SFM + 1 host module + 2 PCGs + 4 PICs =
7 A + 2.4 A + 1.3 A + 1.3 A + 2(0.2 A) + 4(0.625 A) =
7 A + 2.4 A + 1.3 A + 1.3 A + 0.4 A + 2.5 A = 14.9 A @ 48 V = 715 W DC
Power consumption for maximum configuration:
Base system + 8 FPCs + 4 SFMs + 2 host modules + 2 PCGs + 32 PICs =
10 A + 8(2.4 A) + 4(1.3 A) + 2(1.3 A) + 2(0.2 A) + 32(0.625 A)
10 A + 19.2 A + 5.2 A + 2.6 A + 0.4 A + 20 A = 57.4 A @ 48 V = 2755 W DC
Input current from a DC source other than 48 V (based on maximum
configuration):
(54 VDC input) x (input current X) = (48 VDC input) x (input current Y)
54 x X = 48 x 57.4 A
X = 48 x 57.4 A/54 = 51.0 A
System thermal output for maximally configured router:
105% of Watts DC/0.293 = BTU/hr
1.05 x 2755/0.293 = 9873 BTU/hr
Power Requirement (Amps)
7-10 A/48 V
1.3 A/48 V
2.4 A/48 V
0.2 A/48 V
1.3 A/48 V
=