Omron SX-F Instruction Manual page 142

High power direct torque control inverters
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Process and Application Parameters [300]
134
rpm
Motor Speed
3000
[225]
Min speed
300
[341]
Fig. 70
Calculation example of accelerating times (graphics not propor-
tional)
Example
Motor speed [225]: 3000 rpm
Minimum speed [341]: 600 rpm
Maximum speed [343]: 3000 rpm
Acceleration time [331]: 10 seconds
Deceleration time [332]: 10 seconds
Acc>Min speed [335]: 40 seconds
Dec<Min speed [336]: 40 seconds
A. The drive will start from 0 rpm and accelerate to Minimum speed [341] =
600 rpm in 8 seconds according to ramp time parameter Acc>Min speed
[335]. Calculated as following:
600 rpm is 20% of 3000 rpm => 20% of 40 s = 8 s.
B. The acceleration continues from minimum speed level 600 rpm to maxi-
mum speed level 3000 rpm with acceleration rate according to ramp time
Acceleration time [331]. Calculate by following:
3000 - 600 = 2400 rpm which is 80 % of 3000 rpm => acceleration time is
80% x 10 s = 8 s.
This means that the total acceleration time from 0 - 3000 rpm will take 8 +
8 = 16 seconds.
Deceleration Time from Minimum Speed [336]
If a minimum speed is programmed, this parameter will be used to set the
deceleration time from the minimum speed to 0 rpm at a stop command. The
ramp time is defined as the time it takes for the motor to decelerate from the
nominal motor speed to 0 rpm.
Default:
Range:
Communication information
Modbus Instance no/
DeviceNet no:
Profibus slot/index
EtherCAT index (hex)
Max speed
[343]
time
336 Dec<Min Spd
Stp
10.0s
A
10.0 s
0-3600 s
43106
169/10
4c22
Section 11-3

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