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Model
5528A
V.O.l. Compensation
Facior
4.
CALCULATION OF EXACT COMPENSATION
FACTOR
If
the
l
aser Measuremen
t
Syslem
is
being operated in an envi ro
n menl
thai is
not included
in
Ihe
tables
in
this
User's
Gu ide
section,
you
can calcu late
the
exact
compenSJtion
fa ctor
by usi
ng the
following
formulas
to
an accuracy of 0.1
ppm.
CAUTION
The
accur;,u:y of your hser System
Measu rement
is ill function of
your ability
to provide
it with
the correction compensation factor for
your
mea5Urcment
conditions.
When determining the
com-
pensation fador by
ulculation
rather thlln
by
using
the
com-
fH!nsation
fllclor
tllbles, the
result
you get
de
pends
on
the
resolulion of
the
equipment on which you mllke your
calculation
and on your ability
to
ofH!rale it
withoul
error. You
will
be
workins
with
numbers that
are
very
small and
numbers that
are very
large;
even
the
smallest error can
have
ill
significant
effed
on
the
accuracy of your answer, and any error
Is
extremely
dlfflcuilio
detect
or
(rillce. We
strongly suggest
thill'
you
make
a
" practice"
run, using
vililues
from
any of
the
compensation value
tables, to
get
ill feeling
for
whillt
is
required.
In
the
formulas
below
-
T
=
Air
Temperature
P
""
Air
Pressure
1-1
=
Relative Humidity
C
""
Compcnsatio
n
Factor,
to be
entered
manually
,
via
the
Measurement
Display
unit's
front-panc
l
keys.
10
12
C
=
- - -
999000
N+10
6
where
"N" is givcn
in metric
and
English
systems
by -
Melric
:
T
in
degrees
Celsius,
P in
millim
ctrcs of
mcrcury,
1-1
in
' X >
N
""
0.3836391 P
X
[
1
+
10
-6
P
(0.817
- 0.0133T)
]
1
+
0.OO36610T
-
3.033
X
10
~J
H
[c
0057627T]
English
:
T
in degrees
Farcnheit,
P in
inches of
mercury
.
1-1
in
'J{,
N
""
9.74443P
X
[1
+
10
-6 P (26.7
-
O
.l
B7T
)
]
_ 1.089
X
10
-
J
H
[c
003201ST]
0.934915
+
O.OO20388T
19-5
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