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S5-95F on SINEC L1
Conditions for the SINEC L1 Safety Time for Receive
1st condition
The first condition is based upon the principles of the transmitting and receiving system.
Fulfillment of this condition is the basis of the SINEC L1 safety time for the receiving S5-95F:
SINEC L1 safety time for Receive
k= Number of failsafe Send data paths over which the S5-95F (k=1 or 2) or S5-115F (k=1 to 30)
transmitter sends data;
k=1
for one failsafe data path
k=2 to 30
for 2 to 30 failsafe data paths (the data path to the master must also be included in
the case of the S5-115F)
l= Factor for nonfailsafe data paths;
l=0,
when the transmitter never or very rarely sends nonfailsafe data
l=1,
when the transmitter sends nonfailsafe data frequently
n= Number of times the transmitter appears in the SINEC L1 polling list
If the transmitter appears more than once, it must be evenly distributed throughout. A sample
polling list in this case might be: 1 2 3 4 2 5 6 2 7 8 2 9
SINEC L1 bus cycle time =
TIP:
You can reduce the bus cycle time by reducing the amount of data and/or data paths in the
polling list.
2nd condition
The minimum time period between two successive frames from the master to its slave must be
1.5 · the slave's SINEC L1 safety time for Receive.
3rd condition (for double SINEC L1 bus only)
When the S5-95F receives frames from the master, the following condition must be met when using
a double SINEC L1 channel:
SINEC L1 safety time for Receive SINEC L1 safety time for Send + 500 ms
For information on computing the SINEC L1 safety time for Send, see section 13.4.2.
13-26
2·(k+l)·SINEC L1 bus cycle time
Frame size (plus 4 bytes in the case of failsafe frames)×2 ms
+
Number of failsafe data paths in the whole SINEC L1
network×44 ms
n
EWA 4NEB 812 6210-02
S5-95F
+200 ms
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