ABB RELION REG670 Commissioning Manual page 140

Section 12
Testing functionality by secondary injection
The previous calculations are in primary values. They are transferred to secondary values to
perform injections by a test set. Primary values are transferred to secondary values by taking
into account the CT ratio and the VT ratio (respectively 9000/1 A and 13.8/0.1 kV in the
example).
The magnitude of the secondary voltages, that are related to the points RE and SE of the R-X
plane, needs to be checked.
RE (R
FwdR
V
=
t FwdZs ,
EQUATION14054 V1 EN-US
SE (R
RvsR
V V
=
t RvsZs ,
EQUATION14055 V1 EN-US
The tests, which are described in this section, may require voltages that have magnitude equal
to 110% of the previous values. The continuous permissive overload voltage of the protection
voltage channels of the TRM module is 420 V; so the previous voltages may be applied to the
analog channels of the IED continuously. Limitations may be related to the available test set;
the current I
reduce the magnitude of the test voltage for the points RE and SE.
Test sets usually do not have a feature to simulate a real network during a power swing and
apply the related analog quantities at the terminal of the generator. The scope of the present
test is not a simulation of a real network. Voltages and currents are supplied in order to
measure an impedance that changes in the time and traverses the plane R-X and, in particular,
the area inside the lens characteristic. The test may be performed by applying:
• Symmetric three-phase voltage at 50 Hz. The magnitude depends on the point of the
characteristic that needs to be verified. The following three main points of the line
segment SE-RE need to be checked:
•
•
•
The phase angle of the test voltages is equal to:
• arctan (
• arctan (
• Symmetric three-phase current, where the current is the summation of two currents that
have the same magnitude, but different frequencies.
I
50
GUID-F02E8D18-FF87-45BE-8142-E8FA19F6966B V1 EN-US
The first current I
and phase angle 0º.
The second current I
180º (at the starting time of the test) and frequency:
134
, X ):
FwdX
V
0 1 .
VT s ,
V 11931
× = ×
t FwdZ ,
V 13 8 .
VT p ,
, X ):
RvsX
V
0 1 .
VT s ,
5899
× = ×
t RvsZ ,
V 13 8 .
VT p ,
was calculated by using a factor 2.5 (instead of the maximum value 4) in order to
t
the point RE (R , X
FwdR
a point which is related to the parameter
zone 2)
the point SE (R , X
RvsR
ForwardX / ForwardR ) for tests in the quadrant 1 and 2 of the R-X plane
ReverseX / ReverseR ) -180° for tests in the quadrant 3 and 4 of the R-X plane
I 20918
t
I
10459
= = = =
tf
2 2
has frequency 50 Hz, magnitude 10459 A (that is, 1.162 A secondary)
50
has magnitude 10459 A (that is, 1.162 A secondary), phase angle
tf
86 45 . V
=
V
42 75 .
=
)
FwdX
ReachZ1 (boundary between zone 1 and
)
RvsX
A
1MRK 502 067-UEN B
(Equation 14)
(Equation 15)
(Equation 16)
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