Analog Inputs; Analog Outputs - Siemens SIMOVERT FC Series Operating Instructions Manual

Masterdrives cbc - communication board can-bus
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02.99
3.3

Analog inputs

See also block diagram sheets 2 and 3 (Chapter 2) and parameter list (Chapter 4, parameters H100 to H146)
The T100 technology board has 5 analog inputs:
-
2 differential inputs
-
3 single-ended inputs
Signal type
There are three available signal types:
Voltage input ±10 V
-
-
Current input 0...20 mA
-
Current input 4...20 mA
The selection is made via plug-in jumpers and parameters for signal type (see also Tables in block diagram).
Scaling
The %-value which is to represent an input voltage of 10 V or an input current of 20 mA must be set in the
scaling parameter.
Example: Analog input terminals 50/51, voltage input, 5V at input must correspond to 100%
Formula acc. to parameter list - parameter H101:
H101[%] = 10V ∗ Y / X
Therefore: H101 = 10V ∗ 100% / 5V = 200%
Note: In this example, parameter H100 must be set to 0 and plug-in jumper inserted in position 3-4 in
order to select the signal type.
Example: Analog input terminals 54/55, current input, 0...20mA at input must correspond to 0...120%
Formula acc. to parameter list - parameter H121 (H101):
H121[%] = 20mA ∗ Y / X where X = input current in mA
Therefore: H121 = 20mA ∗ 120% / 20mA = 120%
Note: In this example, parameter H120 must be set to 1 and plug-in jumper X3 inserted in position 1-2
in order to select the signal type.
See parameter list and block diagram for setting of other parameters.
3.4

Analog outputs

See also block diagram sheet 4 (Chapter 2) and parameter list (Chapter 4, parameters H150 to H165)
Signal type
There are three available signal types:
Voltage output ±10 V
-
-
Current output 0...20 mA
-
Current output 4...20 mA
The selection is made via plug-in jumpers and parameters for signal type (see also Tables in block diagram).
Siemens AG 6SE7087-6CX84-0BB1
T100 Technology Board Manual for Software Module MS100 "Multi-Purpose Drive"
Terminals 50/51 and 52/53
Terminals 54/55, 56/57 and 58/59
where X = input voltage in volts
Y = %-value which represents input voltage X
Y = %-value which represents input current X
Function Descriptions
3-5

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