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12 CONTROL SUB FUNCTIONS
M
Thus, AP, AL and AM to be set are as follows.
AP = 180224 ...... Pr.2
AL = 67.50000 ... Pr.3
AM = 1 .............. Pr.4
Note): These two examples of settings are only examples. There are
settings other than these examples.)
(4) When "mm" is set as the control unit for conveyor drive
(calculation including
When the belt conveyor drive is used, the conveyor diameter is 135mm,
the pulley ratio is 1/3, the motor is HF-KP (262144PLS/rev) and the
reduction ratio of the reduction gear is 7/53.
Reduction ratio 7/53
As the travel value of the conveyor is used to exercise control, set "mm"
as the control unit.
First, find how many millimeters the load (machine) will travel (
the motor turns one revolution (AP).
•
AP(No. of pulses per rotation) = 262144
S
(Machine travel value per motor revolution)
•
Substitute this for the above expression (1).
At this time, make calculation with the reduction ratio 7/53
as a fraction.
AP
=
S
Here, make calculation on the assumption that
3.141592654.
AP
=
S
or
)
Pulley ratio 1/3
= 135000.0 [
= 135000.0 [
AP
=
AL × AM
135000.0 [ µ m] ×
262144 × 53 × 3
=
135000.0 ×
AP
41680896
=
AL × AM
2968805.058
12 - 17
MELSEC-Q
AP = 180224 ... Pr.2
AL = 0.06750 ... Pr.3
AM = 1000 ....... Pr.4
Belt conver
µ
m]
Reduction ratio
×
×
µ
m]
7/53
×
×
262144 [PLS]
× 7/53 × 1/3
× 7
is equal to
135mm
S
) when
1/3
×
1/3 remaining
×
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