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Si33-102.book Page 102 Tuesday, June 26, 2001 3:18 PM
Appendix
Calculating
Calculate the charge of refrigerant needed as described below, and add accordingly.
Refrigerant Charge
Record your calculations for use by aftercare service.
Total length of liquid line piping (φ 22.2)
+
+
0 :RSXY16,18,24,28KA
0.4:RSXY30KA
+
0.6:RSXY26KA
0.8:RSXY20KA
Outdoor unit
a
A
Outdoor unit
H1
Refnet header
Outdoor unit
Full Refrigerant
The amount of refrigerant needed to completely recharge the system equals to that of the refrigerant
Recharging
charge at factory set (marked on name plate) plus the above additional charge.
Extracting
Open the stop valves on both the gas line and liquid line, and extract the refrigerant from the service ports.
Refrigerant
102
Total length of liquid line piping (φ 19.1)
+
Total length of liquid line piping (φ 5.9)
Total length of liquid line piping (φ 12.7)
+
Total length of liquid line piping (φ 6.4)
Total length of liquid line piping (φ 9.5)
+
Example of refrigerant branch using REFNET joint for RSXY28
REFNET joint (A-G)
H3
Q
g
b
c
d
e
f
H1
B
C
D
E
F
G
p
h
i
j
k
l
m
n
1
2
3
4
5
6
7
H2
8
Indoor units (1-8)
(V1057)
Example of refrigerant branch using REFNET joint and REFNET header for RSXY28
REFNET joint (A-B)
H3
Q
i
a
A
B
k
b
j
7
8
H2
c
d
e
f
g
h
1
2
3
4
5
6
Indoor units (1-8)
(V1058)
Example of refrigerant branch using REFNET header for RSXY28
REFNET header
H3
Q
a
H1
i
b
c
d
e
f
g
h
1
2
3
4
5
6
7
H2
8
Indoor units (1-8)
(V1059)
: http://splitoff.ru/tehn-doc.html
(V1886)
a : φ 22.2 × 10m
i : φ 6.4 × 5m
j : φ 6.4 × 5m
b : φ 22.2 × 2m
c : φ 22.2 × 5m
k : φ 6.4 × 5m
d : φ 19.5 × 5m
l : φ 9.5 × 5m
m : φ 6.4 × 5m
e : φ 15.9 × 5m
n : φ 6.4 × 5m
f : φ 12.7 × 5m
g : φ 9.5 × 5m
p : φ 6.4 × 5m
h : φ 9.5 × 5m
R = 17 × 0.36 + 5 × 0.27 + 5 × 0.17 + 5 × 0.10
a+b+c
d
e
f
+ 15 × 0.05 + 30 × 0.025 + 0
g+h+l
i+j+k+m+n+p
= 6 . 1 2 + 1.35 + 0.85 + 0.5 + 0.75 + 0.75 + 0 = 10.32kg
ò
10.3kg
g : φ 6.4 × 10m
a : φ 22.2 × 30m
b : φ 15.9 × 10m
h : φ 6.4 × 20m
c : φ 9.5 × 10m
i : φ 12.7 × 10m
d : φ 9.5 × 10m
j : φ 6.4 × 10m
k : φ 6.4 × 9m
e : φ 9.5 × 10m
f : φ 9.5 × 10m
R = 30 × 0.36 + 10 × 0.17 + 10 × 0.10
a
b
i
+ 40 × 0.05 + 49 × 0.025 + 0 = 16.72
ò
c+d+e+f
g+h+j+k
16.7kg
a : φ 22.2 × 20m
f : φ 6.4 × 23m
g : φ 6.4 × 20m
b : φ 9.5 × 10m
h : φ 6.4 × 20m
c : φ 9.5 × 10m
d : φ 6.4 × 20m
i : φ 6.4 × 30m
e : φ 6.4 × 10m
R = 20 × 0.36 + 20 × 0.05 + 123×0.025
a
b+c
d+e+f+g+h+i
= 7.2 + 1.0 + 3.07 = 11.27
ò
11.3kg
(V1668)
General Information

SiE33-102

(V1666)
(V1667)

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