Michell Instruments Condumax II User Manual page 86

APPENDIX F
Examples of fl oating point to HEX are shown below.
1) +10.3
sign bit = 0
Exponent = 3, therefore exponent fi eld = 127 + 3 = 130, and bits 30 to 23 = 1000 0010
The mantissa = 1.2875 which in binary representation = 1010 0100 1100 1100 1100 1101
Adjusting the mantissa for the exponent moves the decimal point to the right if positive
and to the left if negative.
As the exponent is = 3 then the mantissa becomes = 1010 0100 1100 1100 1100 1101,
therefore:
1010 = (1x2 ) + (0x2
3
0100 1100 1100 1100 1101 = (0x2
Therefore the word value = 0100 0001 0010 0100 1100 1100 1100 1101
Consequently for sensor 1 register 0001 = 4124 and register 0002 = CCCD
2) - 0.0000045
sign bit = l
Exponent = -18, therefore exponent fi eld = 127 + (-18) = 109 , and bits 30 to 23 =
0110 1101
The mantissa = 1.179648 which in binary representation = 1001 0110 1111 1110 1011 0101
i.e. (1x2 ) + (1x2
-18
Therefore the word value = 1011 0110 1001 0110 1111 1110 1011 0101
Consequently for sensor 1 register 0001 = B696 and register 0002 = FEB5
78
) + (1x2 ) + (0x2
2 1 0
) +(1x2
-1
= 4124CCCD
) + (1x2 ) etc.. = 0.0000045
-21 -23
= B696FEB5
Condumax II User's Manual
) = 10 and
) + -- + (1x2 ) = 0.3
-2 -20
97081 Issue 28.1, July 2018