Humidity And Enthalpy / H,X - Honeywell EXCEL 5000 User Manual

EXCEL CARE CONTROL ICONS ALPHABETIC REFERENCE
For other types of heating systems, reset of the curvature value is not important
where high flow temperatures cannot cause any damage.
Heating Curve Adaptation
The controller can use mean values of the room, outside air, and flow temperatures
to automatically and gradually adjust the heating curve.
The controller measures room temperature throughout the day. On the third day, the
controller starts correcting the heating curve by adapting it to average room
temperature. If the curvature value is too high (for example, 1.6), the flow
temperature during the first few days may also be too high. Adaptation over a
relatively long period of time results in a well-adjusted heating curve.
If you use a sample room to test the adaptation function, make sure there is NO
thermostatic radiator valve (where the room sensor is installed). The radiator in the
sample room must always be open otherwise automatic adaptation does not
function or the results are interpreted incorrectly. Too frequent airing and open
windows in the sample room also have a negative effect on the adaptation
procedure.
If no room sensor is installed, the controller functions as a weather-compensated
controller with the default heating curve setting.

Humidity and Enthalpy / H,X

Function Calculate enthalpy (h) and absolute humidity (x) as a function of air temperature,
relative air humidity, and air pressure. Use H,Xwith the ECO function.
Calculate enthalpy (Ent) and absolute humidity (HAbs) as a function of air
temperature, relative air humidity, and air pressure. Use Enthalpy with the Economy
function.
Formula Absolute humidity (Y2):
Y2 = 0.622 * (X2/100 * PDS) / (P3 – X2/100 * PDS)
Enthalpy (Y1):
Y1 = k1 * X1 + Y2 * (K2 + k3 * X1)
Where:
PDS is the saturation pressure of water vapor (in Pa units):
k1 is the specific heat capacity of dry air (0.2398 Btu/lb °F)
k2 is the heat of evaporation (1061.37 Btu/lb)
k3 is the specific heat capacity of water vapor (0.4443 Btu/lb °F)
k4 is 0.4204 psi
k5 is 0.9202
k6 is 8.00
The calculation assumes a constant air pressure which is input as an internal
parameter.
121 74-5577–33 (US)
EN2B-0184 GE51 R0518 (Europe)