Kinetic energy
Allowable kinetic energy is shown in Table 7.
Since the rotary actuator reaches the rotation end in the middle of acceleration, terminal acceleration
"ω" can be found with the calculation shown below:
ω = 2θ / t
Kinetic energy E can be found with the formula below:
2
E = 1 / 2・I・ω
2
2
I
t =
E
E:Kinetic energy
I :Moment of inertia
θ::Rotating angle
During uniform acceleration, angular speed ω after t seconds and
ω =
x t
θ = ∫
t d t = 1 / 2
When t = 0, rotation angle θ = 0, so the integration constant is C = 0.
θ = 1 / 2
Therefore,
ω = 2 θ / t
Size
10
15
20
30
40
θ::Rotating angle
t::Rotation time
Therefore, rotation time "t" of the rotary actuator is as shown below.
(J)
2
(kg / m
)
(rad)
displacement angle θ can be found as shown below.
t
2
+ C
2
t
= 1 / 2 ω t
Table 7
Allowable kinetic energy
Single Vane
0.00015
0.001
0.003
0.02
0.04
o
180
= 3.14 rad
C is integration constant.
34
Unit (J)
Double Vane
0.0003
0.0012
0.0033
(rad)
(s)
(1)
(2)
D
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